大师作文网(2m-n)(n-2m)-9n-m)2
来源：学生作业帮助网 编辑：作业帮 时间：2024/09/22 01:38:53
(2m-n)/(n-m)+m/(m-n)+n/(n-m)=(2m-n)/(n-m)-m/(n-m)+n/(n-m)=(2m-n-m+n)/(n-m)=m/(n-m)欢迎采纳!
(m-n)2(n-m)7
m/(m-n)^2-n/(n-m)^2=m/(m-n)^2-n/(m-n)^2=(m-n)/(m-n)^2=1/(m-n)
2-n-1-m+m+2-m=3-m-n
(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2
(m-n)^2+n(n-m)原式＝(n－m)^2+n(n-m)=(n-m)（n-m+n）=(n-m)(2n-m)因为完全平方所以(m-n)^2=(n－m)^2(a-b)(3r-t)+9(b-a)(2t
2+n(m-1)/m-m(n-2)/n
2m-n／n-m+m／m-n+n/n-m=(2m-n-m+n)/(n-m)=m/(n-m)
（n-m)^3×(m-n)^2-(m-n)^5=-(m-n)^3*(m-n)^2-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5
(3m-2n)²+(3m+2n)(3m-2n)-9(m+n)²=(3m-2n)²-9(m+n)²+(3m+2n)(3m-2n)=(3m-2n+3m+3n)(3m
原式=(m²-n²-m²+2mn-n²+2mn-2n²)÷4n=(-4n²+4mn)÷4n=-4n²÷4n+4mn÷4n=-n+m
（m+2n）-6（m+2n）（2m-n）+9（n-2m）=[m+2n+3(n-2m)]^2=(5n-5m)^2=25(n-m)^2
2m(m-n)平方-2n(n-m)平方=2m(m-n)^2-2n(m-n)^2=(2m-2n)(m-n)^2=2(m-n)^3
设m-n为a（a^2*a^3）^2/a^4=a^6即（m-n）^6
(m-2n)/(2m+n)=3m-2n=6m+3n5m+5n=0m=-n[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)]-{9(m-2n)/[4(2m+n)]}=[3(-n-2n)/(
﹙m－n﹚²＋2n﹙m－n﹚＝﹙m－n﹚﹙m－n＋2n﹚＝﹙m－n﹚﹙m＋n﹚.
4m^2(m-n)+4n(n-m)=4m^2(m-n)-4n(m-n)=4(m-n)(m^2-n)
m-n+2n^2/(m+n)=[(m-n)(m+n)+2n^2]/(m+n)=(m^2+n^2)/(m+n)
m(m-n)^2+n(n-m)^2=m(m-n)^2+n(m-n)^2=(m-n)^2(m+n)=(m+n)(m-n)^2
(m+n)(m-n)(m^2+n^2)=（m^2-n^2)(m^2+n^2)=m^4-n^4再问：确定？再答：平方差公式再问：没有学过