1x(1 2)-(1 2)x(1 2 3)-(1 2 3 4).......
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=x^18+x^15+x^12+x^9+x^6+x^3+1+x^3-1+5-4分解因式把下面的18换成21就是了=(x^18+1)+(x^15+1)+(x^12+1)+(x^9+1)+(x^6+1)+
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583
2x(x-1)-x(3x+2)=-x(x+2)-122x^2-2x-3x^2-2x=-x^2-2x-122x^2-3x^2+x^2-2x-2x+2x=-12-2x+12=0-2(x-6)=0x-6=0
(x+2-12/x-2)/(4-x)/(x-2),其中x=-1/2=(x²-4-12)(x-2)÷(4-x)/(x-2)=(x²-16)/(4-x)=-(4-x)(4+x)/(4-
两边同时乘以x(x+4)(x+12)4x(x+12)=3(x+4)(x+12)+x(x+4)4x²+48x=3(x²+16x+48)+x²+4x144+4x=0得x=-3
每个绝对值里都是正数所以原式=x+1+x+3+x+5+……+x+13-x-2-x-4-x-6-……-x-12=x-1*6+13=x+7=π/2+7
x平方-6x+8=x²-2×3x+9-9+8=(x-3)²-1=(x-3-1)(x-3+1)=(x-4)(x-2)x平方+x-6=(x-2)(x+3)12+x-x平方=(4-x)(
=[(x+6)(x-2)/(x²+x+1)][(x+1)(x-1)/(x-2)²]{(2-x)/[(x+6)(x-1)]}=-(x+1)/(x²+x+1)
60X+15X+10X+6X=12091X=120X=120/91
x/2+x/6+x/12+x/20+x/30+x/42=136x/42=1x=7/6
应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x
1/6x+1/12x+1/7x+5+1/2x+4=x2/12x+1/12x+6/12x-12/12x+1/7x=-9-1/4x+1/7x=-9-7x+4x=-9*28-3x=-9*28x=84
原式化简:{(x-3)(x-2)/(x-3)(x-4)}²÷{(x+1)(x+2)/(x-4)(x+2)}²{(x-2)/(x-4)}²÷{(x+1)/(x-4)}
(x²-7x+12)(x²+x+1)>0因为x²+x+1=(x+1/2)²+3/4>0所以(x²-7x+12)>0(x-3)(x-4)>0x>4或x
分步写,好让看的清楚符号[√(x^2-6x+9)/x^2-x-12]=√(x-3)^2/(x-4)(x+3)=(x-3)/(x-4)(x+3);(x^3-16x)/(x^2-3x)=x(x^2-16)
原式=(x-1)(x^15+x^14+……+1)/(x-1)=(x^16-1)/(x-1)=(x^8+1)(x^4+1)(x²+1)(x+1)(x-1)/(x-1)=(x^8+1)(x^4+
x^3+x-30(分解因式)=(x^3-27)+(x-3)=(x-3)(x^2+3x+9)+(x-3)=(x-3)(x^2+3x+9+1)=(x-3)(x^2+3x+10);x^12-y^12;=(x
题你是不是抄错了.我算了,如果是x²(x-1)²-4x(x-1)-12=(x(x-1)-6)(x(x-1)+2)=(x-3)(x+2)(x²-x+2)如果是x²
=x^2+10x-24+x^2+15x+56-x^2+5x+50=x^2+30x+82=4+60+82=146其实,不化简,直接代入=14*0+9*10+7*8=0+90+56=146也很简单
答:结论是无解的设1和4中间的正方形边长为x则左边中间的正方形边长为x+1左下角边长为x+1+x=2x+1所以:右下角正方形边长2x+1+x-4=3x-3所以:最大的正方形底部边长=2x+1+3x-3