(2x^2 y)^2-x^2 因式分解-搜答案-大师作文网

x²-4y²+x-2y=(x²-4y²)+(x-2y)=(x-2y)(x+2y)+(x-2y)=(x-2y)(x+2y+1)很高兴为您解答,祝你学习进步!【学习

a(y-x)-2b(x-y)=a(y-x)+2b(y-x)=(y-x)(a+2b)

x（y-x）+y(y-x)-（x-y）^2=-x(x-y)-y(x-y)-(x-y)^2=(x-y)(-x-y-x+y)=-2x(x-y)a^5-a=a(a^4-1)=a(a^2+1)(a^2-1)=

x²(3x+2y)²-y²(2x+3y)²=[x(3x+2y)-y(2x+3y)][x(3x+2y)+y(2x+3y)]=(3x²+2xy-2xy-3

9(x-y)^2+12(x^2-y^2)+4(x+y)^2=[3(x-y)]^2+2*3(x-y)*2(x+y)+[2(x+y)]^2=[3(x-y)+2(x+y)]^2=(5x-y)^2

2x(4-y)再问：麻烦写下过程

解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²

x^2-x-4y^2+2y=(x^2-4y^2)-(x-2y)=(x+2y)(x-2y)-(x-2y)=(x-2y)(x+2y-1)

利用a^3+b^3=(a+b)(a^2-ab+b^2)=(a+b)((a-b)^2+ab)其中125(x-y)^3=(5x-5y)^3为方便计算令2x-3y=a;3x-2y=b;5x-5y=c且a+b

原式=x(x²y+3)-2y(x²y+3)=(x²y+3)(x-2y)

x^2(y-z)+y^2(z-x)+z^2(x-y)=x^2y-x^2z+y^2z-y^2x+z^2x-z^2y=y(x^2-z^2)-xz(x-z)-y^2(x-z)=y(x+z)(x-z)-xz(

(x+3y)(x-y)

原式=[3(x+y)]²-(x-y)²=[3(x+y)+(x-y)][3(x+y)-(x-y)]=(4x+2y)(2x+4y)=4(2x+y)(x+2y)

x^2-xy+y^2 分解因式

你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=（x-y/2）^2+3y^2/4恒大于0,无法分解

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]=(x+y)(x-y)(x²-y²-x²-y²)=-2y²(x+

x^4-y^4+4x^2+4（分组分解法）=(x^4+4x^2+4)-y^4=(x^2+2)^2-y^4（公式法）=(x^2+2+y^2+2)(x^2-y^2+2)(公式法)4x^2-12xy-c^2

(x+y)^4+(x+y)^2-20＝[﹙x＋y﹚²＋5﹚][﹙x＋y﹚²－4]＝﹙x²＋2xy＋y²＋5﹚﹙x＋y－2﹚﹙x＋y＋2﹚

(2x+y)^2-(x+2y)^2=[(2x+y)-(x+2y)][(2x+y)+(x+2y)]=(2x+y-x-2y)(2x+y+x+2y)=(x-y)(3x+3y)=3(x-y)(x+y)

用提取公因式法,提取（x+3y)原式=（x+3y)[(3x-4y)-(x-2y)]=(x+3y)(2x-2y)=2(x+3y)(x-y)

(x+2y)²+x+2y=（x+2y)²+(x+2y)=(x+2y)(x+2y+1）