(3x y)的平方乘以(3x-y)的平方的分解因式-搜答案-大师作文网

当x>y时答案是2分之5当xy时x-y=2y当x

由x-3y=0可知x=3y原式=(2x+y)(x-y)/(x-y)²=(2x+y)/(x-y)=(6y+y)/(3y-y)=7y/2y=7/2

x/y=3所以x=3y(x²+2xy-3y²)/(x²-xy+y²)=(9y²+6y²-3y²)/(9y²-3y&sup

=1/2x²y³*9x²y²+4x²y²*x³y³+1/16y²*8x³y³=9/2x^4

根号和平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等于0所以x+y+7=0xy-5=0x+y=-7,xy=53x^2y^3+3x^3y^2=3x^2y^2(x+y)=3

式子是这样么(2x+y)/(x^2-2xy+y^2）=(2x+y)/(x-y)^2x-3y=0x=3y代入原式(2*3y+y)/(3y-y)^2=7/4yy不能等于0

x减1分之x平方减1,化简为x+1得2005+1=2006第二问不太清楚

原式=3分之1*(x²-3xy-10y²)=3分之1*(x-5y)(x+2y)

x-3y=0x=3y原式=(2x+y)(x-y)/(x-y)²=(2x+y)/(x-y)=(6y+y)/(3y-y)=7y/2y=7/2

(-2x²y³)²×(xy)³=4(x^4)(y^6)×x³y³=4(x^7)(y^9)

x的平方+x-6/x-3/x+3/x的平方-6-x=(x+3)(x-2)/(x-3)×(x-3)(x+2)/(x+3)=(x-2)(x+2)=x²-4x的平方+2xy+y的平方/xy-y的平

2xy²+3x³-x²yx降幂就是x的次数越来越低那么变为3x³-x²y+2xy²

=(x+2y)(x-2y)/(x+2)²×(x+2)/3x(x+2y)=(x-2y)/3x(x+2)=(x-2y)/(3x²+6x)

原式=(3x²+7xy+2y²)(x-2y)=(3x+y)(x+2y)(x-2y)=(3x+y)[x²-(2y)²]=(3x+y)(x²-4y

原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)

(x-3y)(x+y)+2xz+10yz-8z²十字相乘x-3y4z×x+y-2z所以原式=(x-3y+4z)(x+y-2z)=2

(x-y)^2(x-y)^3*(y-x)^2*(y-x)^3=-(x-y)^2(x-y)^3*(x-y)^2*(x-y)^3=-(x-y)^10

（2X的平方Y-XY）乘以3XY=6X³Y²-3X²Y²

x九次方y

最高次项就是各项的最高项相乘,即-3y^2*y^2*2y^4=-6y^8