(5a^2 4b^2)6a^4
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①原式=(a-5b)(a+5b)/5ab*2a/a-5b*4b/3(a+5b)=8/5②原式=(9-a)(9+a)/(a+3)^2*2(a+3)/a-9*a+3/a+9=-2很高兴为您解答,【学习宝典
从楼主给出的一列来看,有如下的规律f(n)=n/2*a+(n/2-1)*b当n是偶数时f(n)=(n-1)/2*(a+b)当n是奇数时
a*a+b*b+a-2b+5/4=0a*a+a+1/4+b*b+-2b+1=0(a+1/2)²+(b-1)²=0a=-1/2,b=1【a-b】/【a+b】=(-3/2)/(1/2)
=4*A^2-(6*A^2-15A*B)-(20A*B-4*B^2)=4*A^2-6*A^2+15A*B-20A*B+4*B^2=2*A^2-5A*B+4*B^2
6a²-5a(-a+2b+1)+4a(-3a-5/2b-3/4)=6a²+5a²-10ab-5a-12a²-10ab-3a=-a²-20ab-8a=-
因为a*b=2×a+b,所以:a*2a=2a+2a=4a,4a*3a=4a×2+3a=11a,11a*4a=11a×2+4a=26a,26a*5a=26a×2+5a=57a,57a*6a=57a×2+
=4a^2-b^2+3(4a^2-4ab+b^2)+(-9a^2+12ab)-2a^2+3=4a^2-b^2+12a^2-12ab+3b^2-9a^2+12ab-2a^2+3=5a^2+2b^2+3当
:((a+b)(a-b)-(a-b)^2+2b(a-b))/4(a-b)=(a-b)[(a+b)-(a-b)+2b]/4(a-b)=(a-b)[2b+2b]/4(a-b)=
采纳吗?再答:采纳就答再问:快点再答:OK!再答:2/5再答:要过程吗再问:要再答:
=24*(a+2b)^4
∵(5a+6b)-(-a-4b)=6a+10b=0;∴a/b=-5/3,5a+6b=-25b/3又∵5a+6b=-25b/3=c-2b∴c=-b/3∴a:b:c=-5:3:-1
(a+3a+5a+...+2013a)-(2a+4b+6a+...+2012a)的答案,急=a{(1+2013)x[(2013-1)÷2+1]-(2+2012)x[(2012-2)÷2+1]}=201
(3a+2b)(6a-5b)(2b-3a)(5a+6b)=(2b+3a)(2b-3a)(6a-5b)(6a+5b)=(4b²-9a²)(36a²-25b²)=3
(a+3a+5a+……+2013a)-(2a+4b+6a+……+2012a)=a-2a+3a-4b+5a-6a+……+2011a-2012a+2013a=-a+3a-4b-a-a-……-a+2013a
当a>0时A-B=(a-1)(a^5+a^3+a)+1=(((((a-1)a+1)a-1)a+1)a-1)a+10Ba>1时A-B>0A>B再问:这个看的好晕A-B=(a-1)(a^5+a^3+a)+
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(-2a^2b)^2-(3a^3b^2)÷5a^2b^2+7a^9b^6÷2a^5b^4=4a^4b^2-3a/5+7a^4b^2/2=15a^4b^2/2-3a/5再问:追问计算:a^3b^2÷1/
a*a+b*b-2a+4b+5=0.即(a-1)^2+(b+2)^2=0.∴a=1,b=-2.代入原式=-2.
(3a-6b)/(a+b)-(5a-6b)/(a-b)-(4a-5b)/(a+b)-(7a-8b)/(a-b)=(3a-6b)/(a+b)-(4a-5b)/(a+b)-(5a-6b)/(a-b)-(7
化简的=(3a-6b-4a+5b)/(a+b)-(5a-6b-7a+8b)/(a-b)=(-a-b)/(a+b)-(-2a+2b)/(a-b)=-1-(-2)=1