(6x-2) (x^2 3x 2)=5-(2x^2 6x 4) (3x 1)
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原式=x³-6x²-9x-2x²+12x+18-(x²-5x)(x-3)=x³-8x²+3x+18-(x³-3x²-5x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(x-1)(x+1)]=[7/x
原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)=1/(x-3)-6/(x-3)(x+3)-(x-1)/2(x+3)=
1/(x²+3x+2)=[(x+2)-(x+1)]/(x+1)(x+2)=1/(x+1)-1/(x+2)同理1/(x²+5x+6)=1/(x+2)-1/(x+3)1/(x²
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
等式两边同时乘以(x+3)(x-2)(x+2)就可以去分母了
(x^2+x+2)(x^2+x+7)-6=(x^2+x)^2+9(x^2+x)+14-6=(x^2+x)^2+9(x^2+x)+8=(x^2+x+1)(x^2+x+8)
原式=9x+6x2-3x+2x2=8x2+6x,当x=-1时,原式=8×(-1)2+6×(-1)=8-6=2.
x^2-x-6>0x3所以A={x|x3}log4(x+a)
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31)x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)=1/x-1/
解方程:x2-6x+2x2-6x=3x2-3x-3-9x=-3x=1/3解不等式:2x3-6x2+4x2-4x≥2x3-2x2+5x-39x-3≤0x≤1/3
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
因为X*根号(X^2+3X+18)-X*根号(X^2-6X+18)=1则X*根号(X^2+3X+18)=X*根号(X^2-6X+18)+1两边平方得X^2*(X^2+3X+18)=1+X^2*(X^2
x=0.问下那个根号x2是不是根号x的平方的意思啊.再问:是的,有没有过程再答:有啊。√X²+6x+2-√X²+x-2=x→7x=x故x=0.(化简)
就把(x2+1/x)=y代进去(2(x2+1)/x)+(6x/x2+1)=7化为2y+6/y=7解之得y=3/2或2(x2+1/x)=3/2时无解(x2+1/x)=2时x=1再问:用换元法把(x2+1
(x-4)/(x²+x-2)=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-