1重for循环结构编程,计算n到100之间的奇数的和s,其中n是学号的最后两位.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/22 13:38:05
#include/*用for循环实现*/voidmain(){\x09intn;\x09intm;\x09printf("pleaseinputn\n");\x09scanf("%d",&n);\x0
importjava.util.Scanner;publicclassTest2{publicstaticvoidmain(String[]args){System.out.println("下面将计
while语句:#includeinti=0,sum=0;main(){while(i
这要看你while循环体怎么写的了?1)inti=1,n=0;intsum=0;while(sum1),所以sum=1;循环不会停止;2)doublei=1,sum=0;intn=0;while(su
#includevoidmain(void){intn=0;inti=0;floats=0;floatfTemp=0.0f;scanf("%d",&n);for(i=1;i
publicclassTest{publicstaticvoidmain(String[]args){doublex=0.0;//当前壶中酒for(inti=0;i
int sum(int n){ List<int> list = new List
C语言的.#include"stdio.h"main(){floatn=0;floatsum=0;for(;n
#includeintmain(){intx,i,n;doubley;printf("Inputainteger:");scanf("%d",&x);n=1;y=0.0;for(i=1;i
for(x=n;x>=3;x--)'判断的最小值为3,小于3的值就没有意义{if(!(xmod3)or!(xmod7))'被3除无余数或被7除无余数count+=x;}x=n;while(x-->=4
你好!PrivateSubForm_Click()DimiAsIntegerDimsAsIntegerFori=1To100s=s+iNextiPrintsEndSu
functionans=FOR(n)sum=0;fori=1:nsum=sum+i^i;i=i+1;endans=sum;functionans=WHILE(n)sum=0;i=1;whilei
#includeusingnamespacestd;intf(intn){ints=0,t=1;for(inti=1;i
vari,n,x,y,z:longint;beginreadln(n);fori:=1tondobegininc(x,i);ifiand1=1theninc(y,i)elseinc(z,i);end;
第一题:programceshi1;varm,n,r,k:longint;beginreadln(m,n);k:=m*n;r:=mmodn;whiler0dobeginm:=n;n:=r;r:=mmo
#include//whileintexp1(inttemp1){inti=1;intterm=1;while(i
intn=100;intsum=0;for(inti=0;i
#includeintmain(){inta,b,n;scanf("%d%d%d",&a,&b,&n);intcnt=0,f=0;for(inti=a;i再问:没有学过【10】这个,用最简单的循环语句
#includemain(){inta[100],i=0,sum=0;do{scanf("%d",&a[i]);i++;}while(a[i-1]0)//求奇数和{if(a[i
ivateSubCommand17_Click()DimiAsLong,kAsLong,jAsLong,oAsLongk=Val(Text1.Text)‘要计算的数j=0o=0Fori=1TokIfi