2. 先随机产生100个三位自然数输出,然后输出其中同时是3.5.7倍数的数.
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/10 03:23:47
publicclassRandomNumber{publicstaticvoidmain(String[]args){intn=(int)(Math.random()*1000);int[]
思路:分别产生个、十、百位上的随机数,依次组合在一起#include#include#includeintmain(){inti,tmp;num=0;srand((unsigned)time(NULL
PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(
import java.util.Random;public class EchoTest { public&nb
command1完成第一题,command2完成第二题PrivateSubCommand1_Click()Dimx%(1To10),n%,i%n=1DoWhilen
PrivateSubCommand1_Click()Dima%(1To20),max%,min%max=50min=100RandomizeClsFori=1To20a(i)=Int(Rnd*51+5
#include"stdio.h"#include"time.h"#include"stdlib.h"intmain(){ doublea[56]; inti; sran
#include<stdio.h>#include<stdlib.h> #include<time.h> #define n 
Dimm(99)AsInteger,n(9)AsInteger,iAsInteger,kAsIntegerRandomizeFori=0To99m(i)=Int(Rnd*100)Printm(i);k
生成按钮代码:PrivateSubCommand1_Click()RandomizeFori=1To100t=Int(Rnd()*900+100)IftMod2=0ThenList1.AddItemt
OptionExplicitPrivateSubForm_Click()'定义i循环变量,imax存放最大数,imin存放最小数,数组ishuz下标为1-10DimiAsLong,imaxAsLong
dimsasinteger,aasinteger,basinteger,casintegers=Rnd()*900+100a=s\100b=s\100-a*10c=smod100-b*10然后用if判
其实……第1、3、8、9、10题都是以前留过的作业……我记得都考给过你…U盘里应该有吧?…话说……太懒了吧……让我每个建一个java格式文件……【没戏!==|||】于是乎……好好上U盘里找找…………好
PrivateSubCommand1_Click()Dimk,a(1To30)Fori=1To30a(i)=Int(Rnd*800+100)Forj=1Toi-1Ifa(i)=a(j)Theni=i-
#include<stdio.h>#include<stdlib.h>#include<time.h>#defineM20voidmain(){inta[M],i;
Private Sub Command1_Click() Dim a%(0 To 19), b
programlx;varn:integer;beginrandomize;n:=random(3);ifn=0thenwriteln(random(100),'+',random(100),'-',
PrivateSubCommand1_Click()DimiAsInteger,xAsInteger,sAsLongRandomizeFori=1To30x=Int(Rnd*100)+1Printx,
vb6测试通过PrivateSubCommand1_Click()Dima(10)AsInteger,tempAsInteger,iAsInteger,jAsIntegerRandomizetemp=
Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim