(lg5)² lg2*lg50的值为

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(lg5)² lg2*lg50的值为
对数运算:(lg5)的平方+lg2*lg50根号下(lg5的平方-2lg5+1)

(lg5)^2+lg2*lg50=(lg5)^2+lg2*(lg2+2lg5)=(lg5)^2+2lg5*lg2+(lg2)^2=(lg5+lg2)^2=(lg10)^2=1根号下[(lg5)^2-2

lg5的平方加lg2乘lg50

(lg5)^+lg2xlg50=lg5^+lg2x(lg2+2lg5)=lg5^+lg2^+2lg2lg5=(lg5+lg2)^2=(lg10)^2=1

(lg5)的平方+lg2*lg50=多少?

lg5*lg5+lg2*lg50=lg5*lg5+lg2*(lg5+lg10)=lg5*(lg5+lg2)+lg2*lg10=lg5*lg10+lg2*lg10=lg10*(lg2+lg5)=lg10

(lg5)的平方加上lg2乘以lg50=多少

(lg5)^2+lg2×lg50=(lg5)^2+lg2×[lg2+lg(5^2)]=(lg5)^2+(lg2)^2+2×lg5×lg2=(lg5+lg2)=lg(5×2)=1

:(lg5)的2方+lg2乘lg50

(lg5)^2+lg2*lg50=lg5*lg5+lg2*(lg5+lg10)=lg5*lg5+lg2*(lg5+1)=lg5*lg5+lg2*lg5+lg2=lg5(lg5+lg2)+lg2[这一步

高中对数运算求出(lg5)^2+lg2*lg50的值,

(lg5)^2+lg2*lg50=lg5*lg5+lg2(lg10+lg5)=lg5*lg5+lg2*1+lg2*lg5=lg5(lg2+lg5)+lg2=lg5+lg2=1

求值 :lg5²+lg2*lg50+(lg2)²

lg5²+lg2*lg50+(lg2)²=2lg5+lg2*lg(5*10)+(lg2)²=2lg5+lg2*(lg5+lg10)+(lg2)²=2lg5+lg

计算:(lg2)的平方+lg2*lg5+lg50!

lg2(lg2+lg5)+lg(5×10)=lg2×1+lg5+lg10=lg2+lg5+1=1+1=2

lg50+lg2*lg5+(lg2)^2=

lg50+lg2*lg5+(lg2)^2=(lg2)^2+lg2lg5+lg(25*2)=(lg2)^2+lg2lg5+2lg5+lg2=lg2(lg+lg5)+2lg5+lg2=lg2*1+2lg5

Lg5的平方加上lg2乘以lg50怎么算啊?

(lg5)²+lg2×lg50=(lg5)²+lg2×(lg5+lg10)=lg5×(lg5+lg2)+lg2=lg5+lg2=lg10=1

(lg5)^2 + (lg2)*(lg50)=

(lg5)^2+(lg2)*(lg50)=(lg5)^2+(lg2)*(lg2*25)=(lg5)^2+(lg2)*(lg2+lg5^2)=(lg5)^2+2lg2lg5+(lg2)^2=(lg5+l

(lg5)^2+lg2*lg50 求值

=(lg5)^2+lg2*(lg5+1)=(lg5)^2+(1-lg5)(1+lg5)=(lg5)^2+1-(lg5)^2=1

化简 (lg5)^2+(lg2)lg50

(lg5)^2+(lg2)lg50=(lg5)^2+(lg2)lg5*10=(lg5)^2+(1-lg5)(lg5+1)=(lg5)^2+[1-(lg5)^2]=1

关于指数计算的lg5*lg5+lg2*lg50=?应该是根据换底公式计算.

=lg5*lg5+lg2*(lg5+lg10)=lg5*(lg2+lg5)+lg2*1=lg5+lg2=1

(lg5)²+lg2×lg50

(lg5)²+lg2×(lg5+lg5+lg2)=(lg5)²+2lg2×lg5+(lg2)^2=(lg2+lg5)^2=(lg10)^2=1

lg5²+lg2*lg50化简

lg5²+lg2*lg50化简=lg5²+lg2(lg5×5×2)=lg5²+lg2(2lg5+lg2)=log5²+2×lg2×lg5+(lg2)²

求解(lg5)^2+lg50*lg2

(lg5)^2+lg50*lg2=(lg5)^2+(lg25+lg2)*lg2=(lg5)²+lg5²lg2+(lg2)²=(lg5)²+2lg5lg2+(lg

1 (lg5)^2+lg50*lg2

1.(lg5)^2+lg50*lg2=(lg5)^2+(2lg5+lg2)*lg2=(lg5)^2+2(lg2)(lg5)+(lg2)^2=(lg2+lg5)^2=(lg10)^2=12.log↓b(

(lg5)²+lg2×lg50

(lg5)²+lg2×lg50=(lg5)²+lg2×lg(5×10)=(lg5)²+lg2×(lg5+1)=(lg5)²+lg2×lg5+lg2=lg5×(l

lg2+lg50+lg5怎样计算

原式=lg2*50*5=lg500=2+lg5