(x-9)×4 18=62的解-搜答案-大师作文网

16(x-2)*(x-2)=9(x+3)*（x+3）==>16(x-2)*(x-2)-9(x+3)*（x+3）=0==>[4(x-2)+3(x+3)]*[4(x-2)-3(x+3)]=0==>[7x+

2x=(x-9)+22的解,

2x=(x-9)+222x=x-9+222x-x=22-9x=13

x(x^2-2)+2x^2(x+3)-3x(5x-7)=x(3x^2-9x+17)+2=>x^3-2x+2x^3+6x^2-15x^2+21x=3x^3-9x^2+17x+2=>2x=2x=1

设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y

5X-3=2X+9的解方程

5X-3=2X+9移项3X=12X=12/4X=4请点击下面的【选为满意回答】按钮,

【解法一】【解法二】5x(x+7)(x+4)=5x(x^2+11X)5x(x²+11x+28)-5x(x²+11x)=05x^3+55x^2+140x=5x^3+55x^25x(x

5x-x²/x²-25=x（5-x)/(x+5)(x-5)=-x/(x+5)=9/(-9+5)=-9/4

原式=2X+0.5X=22.5所以2.5X=22.5得出X=22.5/2.5=9再问：谢谢你咯！

(1)(X+7)/(X+6)+(X+9)/(X+8)=(X+10)/(X+9)+(X+6)/(X+5)这类方程重在运算的技巧性,观察分母7+9=10+6;6+8=5+9所以先移项:(X+7)/(X+6

4x^2+2x√(3x^2+x)+x-9=0,——》(4x^2+x-9)^2=4x^2*(3x^2+x),——》4x^4+4x^3-71x-18x+81=(x-1)(4x^3+8x^2-6x+81)=

方程x^2-9x=0的解是

x^2-9x=0x(x-9)=0x1=0x2=9

因为x^2-x-3=0所以x^2-x=3,x^2=x+3故x(x^2-x)-x(6-x)-9=3x-6x+x^2-9=x^2-3x-9=x^2-x-2x-9=3-2x-9=-2x-6x^2-x-3=0

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1/(x²-6x+9)+1/(2x+6)=x/(x²-9)1/(x-3)²+1/[2(x+3)]=x/[(x+3)(x-3)]去分母,等式两边同乘以2(x+3)(x-3)

(x+x)+(x-x)+(xx)+(x/x)=1002x+0+x²+1=100x²+2x+1=100（x+1）²=10²x+1=10或x+1=-10x=9或x=

3x的二次+5x=0x(3x+5)=0x1=0x2=-5/39x的二次=（x-2）的二次9x²-（x-2）²=0（3x+x-2）（3x-x+2）=0(4x-2)(2x+2)=0(2

x+62/x+63+x+68/x+69=x+63/x+64+x+67/x+68可以把x+62看做x解得x=-4所以x+62=-4x=-66

两边乘(3x+2)(x+3)3x²+8x-3-3x²-29x-18=021x=-21x=-1分式方程要检验经检验,x=-1是方程的解