(x-y 4xy除以x-y)
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x/(y-x)
x^2=x的平方‘/’为除以[(x+2y)^2-(x+y)(x-y)-5y^2]/(2x)=[(x^2+4xy+4y^2)-(x^2-y^2)-5y^2]/(2x)=[4xy]/(2x)=2y[(3x
由x-y除以x+2y等于三分之一,得,(x-y)/(x+2y)=1/33(x-y)=x+2y3x-3y=x+2y,3x-x=2y+3y2x=5y解得x=5y/2所以求x-2y除以x+y=(x-2y)/
2X-Y/X+Y=2X+Y/2X-Y=1/2原式=[2(2X-Y)/X+Y]-[4(X+Y)/2X-Y]=2*2-4*(1/2)=4-2=2P.S.第一次为团队答题,好鸡东哦o(∩_∩)o有什么不懂的
y=(2x+3)/(x-1)=[2(x-1)+2+3]/(x-1)=2+5/(x-1)x<1,∴5/(x-1)<0,∴y<2或∵x<1,x-1≠0,变换得y(x-1)=2x+3,即x=(3+y)/(y
x、y互为倒数,则x与y有三个情况.1.当x>0时如:x=2,则y=1/2,所以x÷y=2÷(1/2)=4,所以x÷y=x²2.当x=0时则x÷y=0÷0=0,故没有意义,所以舍去3.当x<
(x-y)(z+y-x+y+2y)÷4y=(x-y)(z-x+4y)÷4y{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y=(x-y)(x+y-x+y+2y)÷4y=(x-y)(4
x/(x+y)=zx=xz+yzx-xz=yzx(1-z)=yzx=yz/(1-z)
(x-y)的平方除以(x-y)的6次方=1/(x-y)的4次方
ln(x-y)/ln(x+y)=ln(x-y-x-y)=ln(-2y)
【(x-y)^2+(x+y)(x-y)】除以2x=(x-y)*(x-y+x+y)/2x=(x-y)*2x/2x=x-y
(x-y)的五次方除以(y-x)的平方除以(x-y)=(x-y)的平方再问:有详细的过程吗?再答:(x-y)的五次方除以(y-x)的平方除以(x-y)=(x-y)的(5-2-1)次方=(x-y)的平方
(x-y)的十次方除以(y-x)的五次方除以(x-y)=(x-y)^10÷(y-x)^5÷(x-y)=(x-y)^10÷[-(x-y)^5]÷(x-y)=-(x-y)^5÷(x-y)=-(x-y)^4
(x-y)/(√x-√y)=(√X+√y)(√x-√y)/(√x-√y)=√x+√y
[(x²-y²)²/(x+y)²]/(x-y)=[(x+y)(x-y)/(x+y)]²/(x-y)=(x-y)²/(x-y)=x-y如果不懂
题目是不是(x^3+y^3)/(x+y)?应该等于x^2+xy+y^2
绝对值项恒非负,两绝对值项之和=0,两绝对值项分别=03x-y=0(1)x+y=0(2)(1)+(2)4x=0x=0,代入(2)y=-x=0(x-y)/(xy)无意义,因此题目错了.