(y2-3x2)dy-2xydx=0
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5x2—3xy—4y2—11xy—7x2+2y2=-2x2-2y2-14xy=-2(x2+y2)-14xy=-14+28=14
再问:你确定吗?再答:我保证再答:亲,那一步不明白可以问再问:你省略了一步吧!再答:能看明白吗再问:no再答: 再答:是不是这部再问:那么第一步是怎么得来的呢?再答:第一步不是你
取Σ为x+y+z=0的上侧Σ的单位法向量n=(i+j+k)/√3取A=(y+1)i+(z+2)j+(x+3)krot(A)=[-∂/∂z(z+2)]i+[-∂/
已知2x=3y,求xy/(x^2+y^2)-y^2/(x^2-y^2)的值2x=3y-->x=(3/2)yx^2=(9/4)y^2xy/(x^2+y^2)-y^2/(x^2-y^2)==(3/2)y*
y^2=x^3-3x^2+2xx^2=y^3-3y^2+2y两式相减得:y^2-x^2=(x^3-y^3)-3(x^2-y^2)+2(x-y)(x-y)(x^2+xy+y^2-2x-2y+2)=0所以
(x²+y²)²+(x²+y²)-6-6=0(x²+y²)²+(x²+y²)-12=0(x²
记u=√(x^2+y^2),则(x,y)→(0,0)时,u→0,问题转化为一元函数极限:lim(u→0)(u-sinu)/u^3,用洛必达法则得结果1/6
十字相乘法原式=(2x-3y)(x+y)
原式=(2x²-3xy+4y²)+(x²+2xy-3y²)=(2x²+x²)+(-3xy+2xy)+(4y²-3y²)=
由2x²-3xy-2y²=0得2-3(y/x)-2(y/x)²=0(2+y/x)*(1-2y/x)=0得y/x=1/2或-2即y=1/2x或y=-2x代入x²+
即(x²+4x+4)+(y²-6y+9)=0(x+2)²+(y-3)²=0所以x+2=y-3=0x=-2,y=3所以原式=(4+4)/(4+27)=8/31
手机不行,希望你能看明白吧,主要考察我们对于圆锥曲线跟圆的知识
6x2-xy-15y2=(2x+3y)(3x-5y)=0,所以x=-3/2y或x=5/3y
x²-2xy+y²/x²-y²=(x-y)²/(x-y)(x+y)=(x-y)/(x+y)因为x=3,y=-5,所以(3-(-5))/(3+(-5))
x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!
=[x+(3-√5)/2*y][x-(3-√5)/2*y]有点牵强,但这是唯一的答案了
由题意可得,y2=3x−3x22由y2≥0可得3x−3x22≥0解可得,0≤x≤2设t=x2+y2=x2+3x−3x22=−12x2+3x=−12(x2−6x)=−12(x−3)2+92∵0≤x≤2又
3x2+2y2-6x=0x2+y2=1/2(6x-x2)=9/2-1/2(x2-6x+9)=9/2-2-1/2(x-3)2当x=3时,Z最大=4.5
实数范围:无复数范围:(x+yi)(x-yi)-(x+yi)(x-yi)