从键盘输入一个正整数n,若能同时被2和3整除,则输出"OK",否则输出"No
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intaddsum(intm,intn){intm,ncin>>m>>n;if(m<n)cout<<"错误,m<n"<<endl;intsu
#include <stdio.h>int main(void){ int n; &nbs
#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次
判断是否存在《=0的值找出最大数判断两边之和大于第三边 两边之差小于第三边(a==b)==c 是错误的判断想 (a==b)返回的是1或者0 在判断==c肯定是错
#includeintfact(intn);usingnamespacestd;intmain(){intn;cin>>n;cout
#includeintfact(intn){if(n==1)return1;elsereturn(n*fact(n-1));}main(){intn;printf("inputanumber:
#include#includedoublefun(intn);intmain(){printf("Inputn:");intn;scanf("%d",&n);doubleS=fun(n);
#includeintmain(){intn,num,max,min;scanf("%d",&n);for(inti=n;i>0;i--){scanf("%d",&num);if(i==n)//初始化
#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a
#includemain(){intn,i,j,k=0,sum=0,a[100];printf("请输入一个数字\n");scanf("%d",&n);for(i=1;i
楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)
#include#includeintfactorial(intn);doublefact(intn);doublepower(intn);intmain(){inti,j;\x05doubleff=
#includeusingnamespacestd;voidmain(){intn,i,j=0,k=0,a[100],b[100];//a[100]用来存放奇数,b[100]用来存放偶数cout
从键盘输入一个自然数N(
#include#include#includemain(){inti,n;longj,k,sum=0;printf("inputthen:\n");scanf("%d",&n);/*n为项数*/fo
PrivateSubForm_Click()Dimi,n,tAsIntegerDimsAsSingles=0t=1n=InputBox("n=")Fori=1Ton-1s=s+t*i/(i+1)t=-
#includeintmain(){intm,n;intsum1=0,sum2=0;scanf("%d%d",&m,&n);for(inti=m;i
#include#includevoidmain(){intn,s,j,i;printf("inputn(n
#include <stdio.h>int main() {int stat[11];int num, i;for&nbs