使用一维数组编程输出Fibonacci数列的前40项,每行输出4项.

修改如下：#include"stdio.h"intmain(){ints[40],i=0,j,num=0,a=0,b=0,c=0;for(i=0;i

#include#include#includeintmain(){inta[15],i,j;srand(time(NULL));for(i=0;i<15;i++)a[i]=rand()%100;fo

#includemain(){inta[15]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};intb=15;inti,j,is,js;for(i=1,is=0;is再问

#include<stdio.h>int main(){int i,j;for(i=0;i<6;i++){for(j=1;j<6-i;j++)

#includevoidmain(){intn,i,j=0,a[1000];for(i=1;i

可用递归算法实现N重循环来实现详细请QQ:115499275以下也许有助于你以下为文件的内容:VERSION5.00BeginVB.FormForm1Caption="Form1"ClientHeig

char*s[12]={"Jan.","Feb.","Mar.","Apr.","May.","Jun.","Jul.","Aug.","Sep.","Oct.","Nov.","Dec."};int

a=[134567911121516171920];b=(diff(a)==1);ind1=find(diff([0b])==1);%序列开始坐标c=diff([0b(end:-1:1)])==1;i

importjava.util.Scanner;publicclassQk{publicstaticvoidmain(String[]args){inti;System.out.println("请指

看看谁的效率高过我importjava.util.Arrays;importjava.util.InputMismatchException;importjava.util.Scanner;publi

#includevoidmain(){inta[10]={1,2,3,4,5,6,7,8,9,10};intb[6]={2,3,4,5,6,7};intc[10],i,j,k=0,n;for(i=0;

#includemain(){intarray[3][4];inti,j,max;for(i=0;i

所要求的程序已经完成,#include<stdio.h>#include<stdlib.h>main(){ inta[100],i,s=0; randomi

#include<stdio.h>void fanxu(int c[], int j);void main(){\x09int 

publicclassTest{publicstaticvoidmain(String[]args){intn=20;int[]array=newint[n];java.util.R

(**生成一维数组,存到C:/Users/zhou/Desktop/11.txt**)Data=Table[w,{w,0,1,0.01}]Export["C:/Users/zhou/Desktop/1

publicclassTest{publicstaticintfib(intn){if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}publicst

#includemain(){inta[3][4]={{1,2,7,8},{3,4,9,10},{5,6,11,12}},b[4],i,j;for(j=0;j

voidmain(){floata[10];float*p=a,max,min,pj=0;inti=0,j;for(;i

#includevoidinput(inta[],intn)//输入{inti;printf("请输入%d个数,用空格隔开\n",n);for(i=0;i