先化简 再求值 x加5 x减1加x减2的平方

原方程为:x+x\2+1-x+x\4+3=x+x\6+5-x+x\8+7整理得：3x\4+4=7x\24+12两边同时乘以24,得18x+96=3x+288,x=12.8

[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+1/(x-1)=[(x-4)/(x+1)(x-1)]÷[(x-4)(x+1)/(x+1)^2]+1/(x-1)=[(x-

原式=【x(x+1)-x】/(x+1)÷【x²-1+1】/(x²-1)=x²/(x+1)÷x²/(x+1)(x-1)=x-1代入x=1原式=1-1=0如果本题有

=(x²-x-x)/(x+1)÷(x²-1+1)/(x+1)(x-1)=x(x-2)/(x+1)×(x+1)(x-1)/x²=(x-2)(x+1)/x取x=2则原式=0

1、=3(x+2)-x=3x+6-x=2x+6把x=-3/2代入得=-3+6=32、2x+y=5x-3y=5(2)*22x-6y=10(3)(1)-(3)7y=-5y=-5/7代入（2）得：x=5+1

（x加1分之x减1加x平方减1分之2x）除以x平方减1分之1=【（x-1）²/（x+1）*（x-1）+2x/（x+1）*（x-1）】*（x+1）*（x-1）=【（x²+1）/（x+

叙述好混乱,看不明白,请写成{[(a+b)/(c-d)]/(e+f)}+[(g-h)/i]之类的表达式

(x+2)(x-2)+(x+2)^2=(x+2)[(x-2)+(x+2)]=(x+2)[2x]=2x^2+4x=...其中X等于1分号2?

原式=(x+1)/x÷(2x²-1-x²)/2x=(x+1)/x÷(x²-1)/2x=(x+1)/x÷(x+1)(x-1)/2x=(x+1)/x*2x/(x+1)(x-1

原式=[(x-1)/(x+1)+2x/(x^2-1)]/[1/(x^2-1)]通分=[(x-1)^2+2x]/(x^2-1)*(x^2-1)=(x-1)^2+2x=x^2-2x+1+2x=x^2+1再

(1-x)/(x+2)+(x²+2x+1)/2÷(x²-1)/x-1=(1-x)/(x+2)+(x+1)²×(x-1)/(x+1)(x-1)=(1-x)/(x+2)+(x

当x等于负二时,(2x加5)(x加1)减(x减3)(x加1)=(-4+5)(-2+1)-(-2-3)(-2+1)=1x（-1）-（-5）x（-1）=-1-5=-6再问：再问几题再答：不客气再问：诺a与

(x²+x-2)分之(1+x)÷[x-2+(x+2)分之3]=(x²+x-2)分之(1+x)÷[(x+2)分之(x²-1)]=[(x+2)(x-1)]分之(1+x)×(x

(2x减1)的二次方减(3x加1)(3x减1)减5x(x减1)=4x²-4x+1-9x²+1-5x²+5x=x+2=-1+2=1

(x-1)(x+2)(x+3)(x+6)+20=0(x-1)(x+6)(x+2)(x+3)+20=0(x^2+5x-6)(x^2+5x+6)+20=0(x^2+5x)^2-36+20=0(x^2+5x

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

再问：很详细，已经看懂了非常感谢！可以再请教一道分解因式的题吗？3x的立方减18x的平方加27x再答：

/>（2x-x分之1+x的平方）除以x分之x-1,其中x=根号2=[2x²-(1+x²)]/x÷(x-1)/x=(x²-1)/(x-1)=(x-1)(x+1)/(x-1)

1/(x-3)+6/(9-x^2)=1/(x-3)+6/(3-x)(3+x)=(x+3-6)/(x-3)(x+3)=1/(x+3)=1/(-2)=-1/2