先化简,再求值,a分之a-4除以(a²-2a分之a 2-)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/08 03:34:26
[(a-2)/a(a+2)-(a-1)/(a+2)^2]除以((a-4)/(a+2)=(a^2-4-a^2+a)/a(a+2)^2*(a+2)/(a-4)=(a-4)/a(a+2)^2*(a+2)/(
[(a-2)/(a²+2a)-(a-1)/(a²+4a+4)]÷(a-4)/(a+2)=(a-2)/(a(a+2))*(a+2)/(a-4)-(a-1)/(a+2)²*(
原式=[a/(a+2)+a/(a-2)]/[a/(a²-4)]=(a-2+a+2)/[(a+2)(a-2)]*(a²-4)=[2a/(a²-4)]*(a²-4)
(a-1)/a÷(a-2+1/a)=(a-1)/a÷(a²/a-2a/a+1/a)=(a-1)/a÷(a²-2a+1)/a=(a-1)/a÷(a-1)²/a=(a-1)/
=[(a²-4)/(a-2)]×1/a(a+2)=[(a+2)(a-2)/(a-2)]×1/a(a+2)=(a+2)×1/a(a+2)=1/a
4/(a^2-4)+2/(a+2)-1/(a-2)=4/(a+2)(a-2)+2(a-2)/(a+2)(a-2)-(a+2)/(a+2)(a-2)=[4+2a-4-a-2]/(a+2)(a-2)=(a
=(a-3)/2(a-2)÷[5/(a-2)-(a+2)(a-2)/(a-2)]=(a-3)/2(a-2)÷(5-a²+4)/(a-2)=(a-3)/2(a-2)×[-(a-2)/(a+3)
原式=(a-1)/(a+2)×(a+2)(a-2)/(a-1)²×(a+1)(a-1)=(a-2)(a+1)=a²-a-2∵a²-a=0∴原式=0-2=-2
(a-1)/(a+2)*(a^2-4)/(a^2-2a+1)÷1/(a^2-1)=(a-1)/(a+2)*(a+2)(a-2)/(a-1)^2*(a+1)(a-1)=(a+1)(a-2)=a^2-a-
(a²+a)(a²-5a+6)分之(2a-a²)(a²+4a+3)=(2a-a²)(a²+4a+3)/(a²+a)(a²
2a-4分之3-a/(a+2-a-2分之5),=(3-a)/2(a-2)÷[(a+2)(a-2)-5]/(a-2)=(3-a)/2÷(a²-9)=(3-a)/2÷[(a+3)(a-3)]=-
(a+2a+1)/(a-1)-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1
原式=(3+a)(3-a)/(a+3)^2x(a+3)/(a-3)a-1/a=-1/a-1/a=-2/a=-2/根号2=-根号2
(a分之a^2+1-2)÷a^2+2a分之(a+2)(a-1),因为a^2=4,所以a=2或-2,又a+2若为0,即a=-2,公式分母为0,公式无意义,所以a=2,然后化简得结果为a-2,其中a=2,
[a/(a-1)]/[a-(2a-1)/a]=[a/(a-1)]/[(a²-2a+1)/a]=a²/[(a-1)(a-1)²]=a²/(a-1)³将a
再问:谢谢了再答:O(∩_∩)O再问:还可以问你问题吗再答:可以再答:不过我也还只是初三党太难的我无能为力啊T^T再问:2x小于4x加1小于0解集?再答:X<负1再问:ab=负一a加b=2b分之一加a
http://ci.baidu.com/ALnuXPtkhX
(a-2)分之a-(a²-2a)分之2a-a分之2=[a(a-2)]分之a²-[a(a-2)]分之(2a)-[a(a-2)]分之[2(a-2)]=[a(a-2)]分之[a²