先化简再求值a²-2ab+b²/a²其中a＝+1b=-1-b²÷()-搜答案-大师作文网

a,b满足|a+√3|+√b-2｛根号（b-2）｝=0a+√3=0b-2=0a=-√3b=22(a平方b-ab)-3(a平方b-三分之二ab)=2a^2b-2ab-3a^2b+2ab=-a^2b=-(

-a^2(2ab^2-2a^3+2b^3)-2ab(-ab^2-a^2b+2a^3)=-2a²(ab²-a³+b³)+2a²b(b²+ab-

原式=ab(a-2b)分之3a²(a-2b)=b分之3a

由|a-b|+√(b-9)=0得a=b=9,所以：(a^2+ab)/b^2×(a^2-ab)/(a^2-b^2)=a(a+b)/b^2×a(a-b)/[(a+b)(a-b)]=a^2/b^2=1

(ab分子a²+b²+2)÷a-b分之a²-b²=（a²+b²+2ab）/ab÷[(a+b)(a-b)/(a-b)]=(a+b)²

1,a平方加2ab加b平方可以写成完全平方式：（a+b)平方2,然后相乘：得（a+b)平方分之（a分之一加b分之一）乘以ab3,（a+b)平方分之（a分之一加b分之一）乘以ab=（a+b)平方分之a+

(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b)=2a+3b-2ab-a-4b-ab-3ab+2a-2b=3a-3b-5ab=3(a-b)-5ab=3x5-5x(-5)=40

(a²-2ab+9b²)/(a²-2ab)÷(2b²-a-2b)/(a-2b)-1/a=(a²-2ab+9b²)/a(a-2b)÷(2b&#

3a^2-3ab/a^2-2ab+b^2=3a(a-b)/(a-b)²=3a/(a-b)当a=8,b=7时原式=3×8/(8-7)=24(2x+3xy-2y)/(x-2xy-y)=(2/y+

-ab*(a^2b^5-ab^3-b)=-a^3b^6+a^2b^4+ab^2=-(-2)^3+(-2)^2+(-2)=8+4-2=10

(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3)÷1/3b=a^2+2ab+b^2-a^2+ab+2b^2-3ab-2/b^4=3b^2-2/b^4=3-2=1再问：2/b^4是什么

2(3ab-a^2)-(2a^2-3^2ab+b^2)=6ab-2a^2-2a^2+9ab-b^2=15ab-4a^2-b^2=15x(-2)x1-4x(-2)^2-1^2=-30-16-1=-47虚

=-b(a²-2ab-b²）=(1/2)²-2*(1/2)*(-1)-(-1)²=1/4+1-1=1/4

化简[(a+b)/(2ab)]^3÷[(a^2-b^2)/(ab)]^2÷{1/[2(a-b)]}^2原式=[(a+b)/(2ab)]^3÷[(a^2-b^2)/(ab)]^2÷{1/[2(a-b)]

（a-2b)(a²+2ab+4b²）-a(a-5b)(a+3b),=a³-8b³-a(a²-2ab-15b²)=a³-8b

a^2表示a的平方1.2*(a^2*b+ab^2)-2(a^2*b-1)-2ab^2-2=2a^2*b+2ab^2-2a^2*b+2-2ab^2-2=0.2.3x^2*y-[2xy^2-2（xy-3/

因为A-B=A/(A+1)AB=A^3/(A+1)所以原式=(-1/A^2)(1/(A+1)）=-1/[A^2（A+1）]

原式=(a+b)(a-b)/ab(a+b)÷(a²+b²-2ab)/2ab=(a-b)/ab×2ab/(a-b)²=2/(a-b)=2/(3+√5-3+√5)=√5/5

-a²b+(3ab²-a²b)-2(2ab²-a²b)=-a²b+3ab²-a²b-4ab²+2a²