-m=5n=6那么-mn=
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由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m
2m²十4mn十2n²-6=2(m²+2mn十n²)-6=2(m+n)²-6=18-6=12
3m-5mn+3n/(-m)+3mn-n=【3(m+n)-5mn】/【3mn-(m+n)】=【3-5mn/(m+n)】/【3mn/(m+n)-1】=【3-5x2】/【3x2-1】=-7/5
m-n=1/5,m^2+n^2=51/25(m-n)^2=m^2+n^2-2mn=1/2551/25-2mn=1/25mn=1(mn)^1005=1
mn/(3m-n)=3,则:(3m-n)/(mn)=1/3,则:2mm/(3m-n)+(6m-2n)/(mn)=2[(mn)/(3m-n)]+2×[(3m-n)/(mn)]=2×3+2×(1/3)=2
答:mn/(m+n)=2分子分母同除以mn得:1/(1/n+1/m)=21/m+1/n=1/2(3m-5mn+3n)/(-m+3mn-n)分子分母同除以mn得:=(3/n-5+3/m)/(-1/n+3
m-n=1/5,m^2+n^2=51/25(m-n)^2=m^2+n^2-2mn=1/2551/25-2mn=1/25mn=1(mn)^1005=1
由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m+n)]/[-(m
m+n=5m-n=6则mn^2-m^2n=mn(n-m)(m+n)^2=m^2+n^2+2mn=25(m-n)^2=m^2+n^2-2mn=364mn=25-36=-11mn=-11/4mn^2-m^
187a3b8:2=36:9
(m+n)²-4mn=m^2+2mn+n^2-4mn=m^2-2mn+n^2=(m-n)^2=(1/2)^2=1/4
-MN(M^2N^5-MN^3-N)=-(-6)^3+(-6)^2-(-6)=258
m-n=1/5(m-n)²=(1/5)²m²+n²-2mn=1/252mn=51/25-1/252mn=50/25mn=1∴(mn)^1002=1
∵mn-n=15①,m-mn=6②,∴①+②得:mn-n+m-mn=21,即m-n=21;①-②得:mn-n-m+mn=2mn-m-n=9,即-2mn+m+n=-9.故答案为21;-9
∵m+n=5,mn=-6,∴(m+n)2 −4mn=52-4×(-6)=25+24=49,故答案为:49.
m+n=4①m-n=6②①+②得:2m=10解得:m=5所以:n=-1故:mn=-5
m-n=1/5①m^2+n^2=51/25②①²-②,得-2mn=1/25-51/25=-2所以mn=1从而(mn)^2013=(1)^2013=1
mm-n=15,m-mn=6两式相加得m-n=21
已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n