函数求奇数和输入一批正整数(以零或负数结束)

eak是直接跳出循环体,不再继续执行将break;改成continue;输入以0或负数结束；例如123450结果为9#include"stdio.h"inteven(intn){if(n%2==0)\

//仅供参考#includeintmain(){intn,sum=0;while(scanf("%d",&n)==1&&n+1){if(n%2==0)printf("%d\n",n);elsesum+

这个题不难呀?怎么没人答?不用pow函数,那就自己写个for循环呀.就是不知道你要求什么语言了,你也不说清楚,C和C++都写了,C语言：#includevoidmain(){inty,i;double

#includeintmain(){voideve(int);inta;printf("pleaseinputanumber");scanf("%d",&a);eve(a);//你的调用格式不对!你的

#include<stdio.h>inteven(intn){    if(n%2==0)     

#includeinteven(inta){if(a%2==0)return1;elsereturn0;}voidmain(void){intnum,odd=0;printf("请输入一批整数,以零或

#includevoidmain(){intnum,sum=0;scanf("%d",&num);while(num>0){if(num%2!=0){sum+=num;}scanf("%d",&num

inta[n],b[n];inti=0,j=0for(i=1;i>k;if(kint(k))continue;if(k%2==0){a[i]=k;i++;}else{b[j]=k;j++;}}cout

#includeintmain(void){intnumber,sum=0;printf("Enternumber:\n");scanf("%d",&number);while(number>0){i

clears=0input'请输入一个正整数：'toxfori=1toxifi%20&&判断i是否为奇数s=s+iendifendfor's=',sreturn（此题是求和问题,循环和用循环语句,因知

(1+(2n-1))n/2;首项是1,尾项是2n-1；直接用求和公式.

填入：sum=0;while(x>0){if(x%2==0)sum=sum+x;scanf("%d",&x);}

#includeinteven(intnum){returnnum%2;}intmain(){intsum=0,num=0;printf("Inputintegers:");while(1){scan

编程c语言输入一批正整数以0或负数为结束标志求奇数的和要求定义和调用函数已在TC2下经过测试,如果觉得好,#include<stdio.h>#

#includeintmain(){intn,i,x,a=0,b=0;scanf("%d",&n);for(i=1;i

用循环.再问：求过程？再答：再答：图片看的清么，刚刚编的，望采纳。再问：还行，我在编译一遍试试再答：嗯，我调试过了，能成功。你再看看吧。再问：有了一点思路，

#includeintcal(intm,intn){intret=0;ret=m%n;returnret;}intmain(intargc,char**argv){intm,n,max,min

占天时地利人和取九州四海财宝横批：财源不断

程序已经编写完成,请采纳:varn:integer;functionfacsum(n:longint):longint;vars,t,i:longint;begins:=0;i:=1;t:=1;whi

正整数列前n个的奇数,首项为1,末项为2n+1,所以：Sn=(1+2n+1)n/2=n(n+1)