分别求两个整数的最大公约数
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/06 10:26:00
privatesubform_click()n=val(text1)m=val(text2)ifn
你的c语言写的好乱,我帮你整理如下:#include "stdio.h"int gcd(int a,int b){ &
packagecom.fmzrt;/***求两个数的最大公约数和最小公倍数*@authorkele**/publicclassGongyueGongbeiShu{/***求两个数的最大公约数*@par
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}intgongbe
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(
include"stdio.h"intgongyue(inta,intb);intgongbei(inta,intb);voidmain(){inta,b,temp,gy,gb;clrscr();pr
275和385最大公约数55,得到的伤分别5,7.
你的题目好像少了些什么提问者好像少给出两商之和..再问:没少再答:你的两商之和没有给啊
PrivateSubCommand1_Click()DimSAsLongS=YueOrBei(24,32)MsgBox"24和32的最大公约数是:"&S,vbInformationS=YueOrBei
1925=5×5×7×11;两个商都是1925的因数且互质,而且和为16,所以这两个商分别为5和11;这两个整数分别是:1925÷5=385,1925÷11=175;答:这两个整数分别是385与175
intmax_common_divisor(inta,intb){//最大公约数intlarge_num,small_num,r;if(a>b){large_num=a;small_num=b;}el
#includeintmaxY(intm,intn){inti;for(i=n;i>0;i--)if(m%i==0&&n%i==0)break;return(i);}intminB(intm,intn
#includevoidmain(){inthcf(int,int);intlcd(int,int,int);intu,v,h,l;scanf("%d,%d",&u,&v);h=hcf(u,v);pr
include"stdio.h"intgongyue(inta,intb);intgongbei(inta,intb);voidmain(){inta,b,temp,gy,gb;clrscr();pr
#includeintmain(){inta,b,imax,imin,tend;intmax(int,int);printf("pleaseinserttwonumbers:");scanf("%d%
例子一:#includevoidmain(){voidz1(inta,intb);intx,y,temp;scanf("%d%d",&x,&y);if(x
#include"stdio.h"voidmain(){\x05intnum1,num2,temp,a;\x05printf("pleaseinputtwonumbers:\n");\x05scanf
1092=2×2×3×7×137+13=202×2×3×7=842×2×3×13=156这两个整数分别是84和156
①#includeinthcf(inta,intb){\x09intc;\x09while(b){c=b;b=a%b;a=c;}\x09returna;}intlcd(inta,intb,intc){
完整程序如下:#includefun(intx,inty){intr;if(x>y){x=x;y=y;}r=x;x=y;y=r;r=x%y;while(r!=0){x=y;y=r;r=x%y;}ret