分解因式(x的二次方2)(x4)x的二次方4
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-16x四次方+81y二次方=(9y+4x^2)(9y-4x^2)不懂可追问,有帮助请采纳,谢谢!再问:数学的寒假作业还没做完==作业要做八下的题都不会咋办再答:不回答追问里的新问题,请采纳了再提问,
x²﹙x-2﹚²-9=﹙x²-2x)²-9=(x²-2x+3)(x²-2x-3)=(x²-2x+3)(x-3)(x+1)
=-xy/2*(4x²-4xy+y²)=-xy/2*(2x-y)²
∵f(x)=x³-3x²+4=0时,有一个根x=-1;∴x³-3x²+4肯定存在(x+1)的因子.∴x³-3x²+4=x³+x&s
(x-2)的2次方-(3x+4)=x^2-4x+4-3x-4=x^2-7x=x(x-7)
x^3+2xy-x-xy^2=x^3-x(y-1)^2=x(x^2-(y-1)^2)=x(x-y+1)(x+y-1)x^3x的3次方的意思^2这是2次方!看得懂吧
x²-5=x²-(√5)²=(x+√5)(x-√5)2a²-6=2(a²-3)=2[a²-(√3)²]=2(a+√3)(a-√3)
=2(x²-2x+2)=2(x+1)²
因式分解都用十字相乘法x^2-9x-36=(x-12)(x+3)x^2-8x-9=(x-9)(x+1)(x+2y)^2-15(x+2y)-16=(x+2y-16)(x+2y+1)应该是x^2+x+1=
x^2+3xy+2y^2+4x+5y+3=(x+y)(x+2y)+3(x+y)+(x+2y)+3=(x+y)(x+2y+3)+(x+2y+3)=(x+y+1)(x+2y+3)
(x²+6x+8)(x²+14x+48)+12=(x+2)(x+4)(x+6)(x+8)+12=[(x+2)(x+8)][(x+4)(x+6)]+12=(x²+10x+1
(1-x^2)(1-y^2)+4xy=1-x^2-y^2+x^2y^2+4xy=(x^2y^2+2xy+1)-(x^2-2xy+y^2)=(xy+1)^2-(x-y)^2=(xy+x-y+1)(xy-
赵易涵,回答如下,(X2+Y2)2-4X2Y2=(X2+Y2-2XY)(X2+Y2+2XY)=(x-y)^2*(x+y)^2=(x^2-y^2)^2.
x³y³-2x²y²+xy=xy(x²y²-2xy+1)=xy(xy-1)²
原式=(x+y)(x+2y)+2(x+2y)=(x+2y)(x+y+2)希望我的回答能帮助到您,
=(9x平方-1)平方=(3x-1)平方(3x+1)平方
(a+2b)(a+b)
M=2x²+3x+1=(2x+1)(x+1)N=4x²-4x-3=(2x+1)(2x-3) 方法是十字相乘法 &
结果是3(x-y)的2次方与(2x-5y)的积3(x-y)的2次方乘以2(x-y)-3(x-y)乘以3y,提取3(x-y)的2次方得3(x-y)的2次方乘以(2x-2y-3y),合并得:3(x-y)的
24可以看成是(-6)乘以(-4)的积.利用十字相乘法,原方程因式分解为:(X-6)(X-4)--------