利用数组计算并输出fibonacci的前二十项讲解
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DimiAsIntegerFori=0To100i=i+1NextResponse.Write(i)
假设无符号整数数组a[10]中已有数据:longmax=0;longmin=999999999;for(i=0;imaxmax=a[i];ifa[i]
窗体中加命令按钮,单击事件代码如下:PrivateSubCommand1_Click() Randomize Dima(1To20)AsInteger&nb
先定义数组ainti=0;intj=0;doublepa=0;for(i=0;i再问:能不能来个完整版的,我一窍不通,谢谢了,再答:c语言或者c++么?再问:是的,c++再答:先采纳吧,十五分钟给你,
voidmain()//C++实现{floatscore[69][3];//存放各人的成绩floatdata[69][2]={0};//存放总分和平均分cout
#include <stdio.h>#include <stdlib.h>#define size 5int main(){&
#include<stdio.h>int main(){\x09int fib[10];\x09fib[0] = 1;\x09fib[1] 
代码如下,有问题可以追问#includevoidmain(){intn;intarr[100][100],sum1=0,sum2=0;inti,j;printf("请输入n:");scanf("%d"
请问你要用什么编程语言来写?再问:C++
int[]a=new[]{4,7,6,9,3,1,5,8,0};Listb=newList(a);b.Sort(delegate(intx,inty){return(y-x);});最大值:b[0]最
char*s[12]={"Jan.","Feb.","Mar.","Apr.","May.","Jun.","Jul.","Aug.","Sep.","Oct.","Nov.","Dec."};int
(1)for(inti=3;i
这样写已经可以实现了,可以编译后执行一下就知道了,不过格式不太规范啊
#includevoidmain(){inta[69][3];inti,j;floateng,phy,math,engavg,phyavg,mathavg;eng=phy=math=0;engavg=
/*下面的程序产生N个随机的整数,存放在数组a中.然后根据数组a建立线性链表,再删除链表中所有重复元素,并输出无重复元素结点的链表结点的值*/#include#include#include/////
int[]arr={2,4,6,8,10,12,14,16};intsum=0;for(inti=0;i
#includevoidmain(){inta[10]={2,3,5,1,8,4,7,9,0,6};inti,s;intmax,min;max=min=a[0];for(i=s=0;imax)max=
#include <stdlib.h>#include <time.h>#include <stdio.h>void mai
inti,geshu=0,sum=0,a[100],aver;scanf("%d",&a[i]);for(i=0;i