利用运算符重载实现集合类的并集

这是我以前写的一个演示程序,正好适合,你给你吧.我对输出做了优化,更符合数学上的习惯.//#include#includeusingnamespacestd;classComplex{//定义复数类d

#includeusingnamespacestd;classCComplex{floatreal;floatimage;public:CComplexoperator+(CComplex&a)

#includeusingnamespacestd;classComplex{public:Complex(){real=0;imag=0;}Complex(doubler,doublei){real

#include再问：感谢你的回答！只是没有实现++和--的重载，能不能再写点？

#include#includeusingnamespacestd;templateclassMySet{public:MySet();MySet(ints,constTypea[]);MySet(c

classcomplex{public:complex(doubler=0,doublei=0){real=r;image=i;}doublereal;doubleimage;};complexope

usingSystem;namespacedoing{classdome{staticvoidMain(string[]args){doublea,b,c;Console.Wr

#include#includeclassComplex{public:Complex():_real(0),_imag(0){}explicitComplex(doubler):_real(r),_

#includeusingnamespacestd;classComplex{doublereal;doubleimag;public:Complex()//默认构造函数{real=0;imag=0;

#include#includeclassComplex{public:Complex(floata,floatb):m_real(a),m_imaginary(b){}Complex():m_rea

#ifndefFRACTION_H_#defineFRACTION_H_#includeintgcd(intm1,intm2);classFraction{public:\x05Fraction(){

前面答案都对,就抄了一下：1.M∩P=｛x｜x＝10n,n∈N｝∩P=｛x|x=15n,n∈N｝=｛x|x=30n,n∈N｝2.A∩B=｛x|24/x∈N*,x∈N*｝∩B=｛x|54/x∈N*,x∈

#includeusingnamespacestd;classcomplex{public:complex():real(0),vir(0){}complex(floata,floatb):real(

1、a≥22,a≥3,3,∵M:x＜-2或x＞4,N:x＜1,或x＞3,∴M∪N=N={x│x＜1,或x＞3}4,B:x≥0∴AUB={x│x＞2},∴A∩B={x│0≤x＜2,x∈Z}={0,1},

#includeusingnamespacestd;classfraction{public:fraction(intn=1,intd=1){num=n;den=d;}fraction&operato

#includeusingnamespacestd;classComplex{floatReal,Image;public:Complex(floatr=0,floati=0){Real=r;Imag

//-------------------------------------//-----------------------------------------------------------

楼主能说清楚点不?用什么语言?

仅供参考.有很多其他的方法也可以的.这里只是一个可能的方案,希望对你有用!#include#includeusingnamespacestd;classtriangle{private:floatar

 #include <iostream>#include<stdio.h>using namespace std;class