24 3x=34 x解

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(

(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

[1-1/(x-4)]+[1-1/(x-8)]=[1-1/(x-7)]+[1-1/(x-5)]1/(x-4)+1/(x-8)=1/(x-7)+1/(x-5)(x-4+x-8)/(x-4)(x-8)=(

(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=(x/2)*(2/x(x+2))+(2/(x+2)(x+4))+.+2/(x+8)(x+10)=(x/2)*[1/x

我给个思路吧（X+2-1/X+2)-(X+3-1/X+3)=（X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决

X/(x-30)=(x+40)/XX^2=(X-30)*(X+40)X^2=X^2+40X-30X-120010X=1200X=120

只有一个实根.设f(x)=x^3+2x-19为单调增函数.所以只有一个实根.下面来求这个实根由于f(2)=-7f(3)=11所以这个根在（2,3）内.利用二分法求这个解.取x0=5/2f(5/2)=1

（X+X)+(X-X)+(X*X)+(X/X)=1002X+0+X*X+1=1002X+X*X=99X(X+2)=99X=9再问：请问X(X+2)=99解为什么就等于9了呢没看懂再答：换成算术法你就明

uzhi

x^3-x^2-2x=0x(x^2-x-2)=0x(x-2)(x+1)=0x=0或x=-1或x=2

本人提供一个解法：由于(x-2004)/(x-2005)=1+1/(x-2005),其它三个分式同样进行拆分,最终得出：[1+1/(x-2005)]-[1+1/(x-2006)]=[1+1/(x-20

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

x+五分之一x=2406/5x=240x=200x-60%x=1600.4x=160x=40050%x-33%x=340.17x=34x=200120x-20x=40100x=40x=0.4x+130

(x+12)*(x+12)=x*x+360x*x+144+24x=x*x+36024x=360-144=216x=216/24=9楼下的你复制我的做什么

(x+x)+(x-x)+(xx)+(x/x)=1002x+0+x²+1=100x²+2x+1=100（x+1）²=10²x+1=10或x+1=-10x=9或x=

30%x=12030x=12000x=400x-60%x=16040%x=16040x=16000x=400120x-20x=40100x=40x=0.450%x-33%x=3417%x=3417x=

（1）X+40%X=28，    （1+40%）X=28，        &nb

问题是不是X2=(X+30)*(X-18）啊?要是上面的话就这样X2=X*X-X*18+30*X-30*18=X2+12X-540移项得：X2-X2-12X=-540,即-12X=-540,X=45*