25分之x的平方-16分之y的平方因式分解
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(x²/25)÷(y²/16)=16x²/(25y²)再问:抱歉,请问能分解因式吗?再答:你这个题不是分解因式的类型,如果改为:(x²/25)-(y&
原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)
(x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=(x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)
=x(x-y)/xy²×y/[-(x-y)]=-1/y
(x分之x-y)-(y分之x+y)+(2xy分之x的平方-y的平方)=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^
①49分之1的x的平方-25分之16y的平方=(x/7+4y/5)(x/7-4y/5)②-0.01+四分之九(a的平方)=(3a/2-0.1)(3a/2+0.1)③49(a-b)的平方-16(a+b)
y=[根号下(x^2-9)+根号下(9-x^2)+16^(1/4)]/(3-x)所以:x^2-9=0,9-x^2=0,3-x不等于0解得:x=-3,代入,求得:y=1/3所以:x/y=-3÷(1/3)
2/(x-y)-(x+y)/(x-y)^2=[(2x-2y)-(x+y)]/(x-y)^2=(x-3y)/(x-y)^2
原式=xy/(x-y)(x+y)÷(2y)/(x-y)(x+y)=x/2再问:再问:
(x^2-4y^)\(x+y)^2乘以2x(x+y)/(x+2y)=2x(x-2y)\(x+y)
(8x^2/9y^2)*(3y/-4x)=-2x/3y不懂请追问,满意请采纳~再问:过程????再答:就相当于(8x的平方除以-4x)乘以(3y除以9y的平方)=-2x乘以3y分之一=负的3y分之2x
(x/2y)²×(y/2x)-x/y²÷(2y²/x)=x²/2y×(y/2x)-(x/y²)×(x/2y²)=x/8y-x²/(
[1/(x-y)-1/(x+y)]/[xy^2/(x^2-y^2)]=[(x+y-x+y)/(x-y)(x+y)]/[xy^2/(x-y)(x+y)]=[2y/(x-y)(x+y)]/[xy^2/(x
(1)2xy的平方分之3x的平方y=(2y)分之3x(注:分子分母约掉xy).(2)(x的平方-25)分之(x+5)=[(x-5)(x+5)]分之(x+5)=(x-5)分之1
平方差=[(3x-2y)/2+(3x+2y)/2][(3x-2y)/2-(3x+2y)/2]=[(3x-2y+3x+2y)/2][(3x-2y-3x-2y)/2]=3x*(-2y)=-6xy
现将括号里的通分x2-y2可约去最后的y分之2再问:能具体一点吗再答:原式=((x+y+x-y)/(x2-y2)÷(x的平方-y的平方分之xy)=2x/(x2-y2)×(x2-y2)/xy=y分之2只
(1-y+x分之y)÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x
x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²