2cos2x等于多少
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/11 12:23:28
(1)根据图信息可知sina=4/5cosa=3/5∴(sina^2+sin2a)/(cosa^2+cos2a)=(sina^2+2sinacosa)/(cosa^2+cosa^2-sina^2)=(
cos2X=(cosX)^2-(sinX)^2=2*(cosX)^2-1
再答:一定等于
1/2*sin2x再问:过程?
(sinx/cosx+cosx/sinx)cos^2x-sin^2x=sinx*cosx+cos^3x/sinx-sin^3x/cosx-cosx*sin=(cos^4x-sin^4x)/(sinx*
f(sinx(π/2-x))=cos(π-2x)f(cosx)=-cos(2x)
题目条件不充分啊cos2x+sin2x=1cos2x=cos^2x-sin^2xsin2x=2sinxcosxcos2x+sin2x=cos^2x-sin^2x+2sinxcosx
cos(A+B)=cosAcosB-sinAsinB(1)cos(A-B)=cosAcosB+sinAsinB(2)(2)-(1)cos(A-B)+cos(A+B)=2cosAcosBA+B=3x/2
sinx/cosx=tanx所以sin2x/cos2x=tan2x
sin2x+cos2x=√2(√2/2sin2x+√2/2*cos2x)=√2(cospai/4sin2x+sinpai/4cos2x)=√2sin(2x+pai&#4
f(sinx)=1-cos2x=2(sinx)^2,既有f(x)=2x^2,故f(cosx)=2*(cosx)^2=1+cos2x.
sin15度=cos75度因为f(cosx)=cos2x所以f(sin15度)=f(cos75度)=cos(2*75度)=cos150度=-cos30度=-根号3/2
cos2x=cos(x+x)=cosx*cosx-sinxsinx=cos²x-sin²x=cos²x-(1-cos²x)=2(cosx的平方)-1
f(sinx)=1+1-cos2x=1+2sin²xf(cosx)=1+2cos²x=cos2x+2再问:1-cos2x=???再答:cos2x=cos²x-sin&su
sinx^2+cosx^2=1,这就相当于一个公式,中间的变数x当然可以换成任何值了!
因为sin^2(X)+cos^2(X)=1所以原式=1-cos^2(x)-cos^2(x)=1-2cos^2(x)=-(2cos^2(x)-1)=-cos2x
原式=∫4cos2x/sin²2xdx=2∫cos2x/sin²2xd(2x)=2∫dsin2x/sin²2x=-2/sin2x+C再问:能把cos2x化成cos&sup
lim(x→0)(1-cos2x)/sinx=lim(x→0)2sin²x/sinx=lim(x→0)2sinx=0
limx0时1-cos2x/sinx=limx0时[(2x)²/2]/x=0