2x-36=204
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X+X-10+X-2=36*33x-12=1083x=120x=40
x+2x×10=10x+2x+36x+20x=12x+3621x-12x=369x=36x=4
(10x2x+2x)-(10x+2x)=3622x-12x=3610x=36x=36÷10x=3.6
36-(3x-10)=x-2x36-3X+10=-X3X+(-X)=462X=46X=233.2x=14.2-1.5x3.2X+1.5X=14.24.7X=14.2X=142/47再问:(-X)是什么
4x+2*(12-x)=362x+24=362x=12x=6
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
42x-6x²=36-6x²+10x42x-10x=3632x=36x=9/8再问:解方程:(x+1)(x+4)=x的2次方-6再答:x²+5x+4=x²-65
7x-2x+3x=365x+3x=368x=36x=4.5
2/3x+36=x移项得:36=x-2/3xx/3=36x=36*3x=108
(1)12x+36-6x=102则:6x=66所以:x=11(2)2x-48-x=54,即:x=54+48=102(3)2x-1+x=14,即:3x=15,所以:x=5
x/2+36%x=431/2*x+9/25*x=4343/50*x=43解得:x=50
(2*3)^(x+1)=36^x6^(x+1)=6^2x所以x+1=2xx=1
56-2x=3(36-2x)56-2x=108-6x4x=52x=13第一步:被除数=商×除数
设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=
2x-36=2042x=240x=120(1-25%)x=360.75x=36x=485x+4分之1*16=345x+4=345x=30x=650%x-35%x=30.15x=3x=20再问:谢谢。请
(7-2+3)X=368X=36X=9/2
x+2+x-2+2x+x÷2=364x+x/2=368x+x=729x=72x=9再带进去检验一下就行,
x/x(x-1)+2=2x/(x+1)1/(x-1)+2=2x/(x+1)x+1+2(x-1)(x+1)=2x(x-1)x+1+2x²-2-2x²-2x=0-x-1=0-x=1x=
25%x=200x=200/25%x=800x+35%x=540x(1+35%)=540x=540/1.35x=400x-0.78%x=8.822%x=8.8x=4048%x-12%x=3636%x=
x=12