2y分之x的完全平方乘2x分之y
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原式=2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)=(2xy+x²-xy)/(x+y)(x-y)=(x²+xy)/(x+y)(x-y)=x(x+y)/(x+y)
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(x的平方-y的平方)分之2xy+(x+y)分之x-(y-x)分之y=(x的平方-y的平方)分之2xy+(x+y)分之x+(x-y)分之y=(x²-y²)分之[2xy+x(x-y)
前者分子:x^2-y^2=(x+y)(x-y)那前面这项就可以化简约分啦后者分子:4x^2-4xy+y^2=(2x)^2-2*2xy+y^2=(2x-y)^2建议你理解一下x^2-2xy+y^=(x-
x-3y=0x=3y原式=(2x+y)(x-y)/(x-y)²=(2x+y)/(x-y)=(6y+y)/(3y-y)=7y/2y=7/2
(xy-x的平方)除以xy分之x的平方-2xy+y的平方乘x的平方分之x-y=x(y-x)*xy/(x-y)²*(x-y)/x²=-y再问:不好意思,打错了(xy-y的平方)除以x
(xy-x²)÷(x²-2xy+y²)/(x-y)×(x-y)/x²=-x(x-y)÷(x-y)²/x²=-x(x-y)×x²/(
(x分之x-y)-(y分之x+y)+(2xy分之x的平方-y的平方)=1-y/x-1-x/y+(x^2-y^2)/2xy=-2(y^2+x^2)/2xy+(x^2-y^2)/2xy=-(x^2+3y^
请把题目说清楚这很容易产生歧义
y=2x/3则xy=2x2/3y2=4x2/9所以原式=(2x2/3)/(x2+4x2/9)-(4x2/9)/(x2-4x2/9)=(2/3)/(1+4/9)-(4/9)/(1-4/9)=6/13+4
=(x+y)(x-y)/(x+y-1)(x-y+1)×(x-y+1)(x-y-1)/(x+y)²×(x+2y)(x-y)/x(x-y)=(x-y-1)(x+2y)(x-y)/x(x+y-1)
[(x²+y²-9)²-4x²y²]/(x²+6x+9-y²)=(x²+2xy+y²-9)(x²-2
原式=[(x+y)/(x-y)]^2*[2(x-y)/5(x+y)-[X/(x^2y^2)]/[x/(x+y)]=2/5-[x/(x^2y^2)]*[(X+y)/x]=2/5-(x^2y^2)/(x+
原式=1/(x+1)*[(x-3)/(x+3)^2+2/(x+3)]-x/(x+3)(x-3)=1/(x+1)[3(x+1)/(x+3)^2]-x/(x+3)(x-3)=3/(x+3)^2-x/(x+
(x-1)^2/(4x)×(2x^2)/(x-x^2)=(x-1)^2/(4x)×(2x^2)/[-x(x-1)]=-(x-1)/2=(1-x)/2
2x/9-7x²/27=16两边乘277x²-6x+432=0判别式=(-6)²-4×7×432
x的平方-64y的平方分之2x-x-8y分之1=[2x-(x+8y)]/(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)
(3y/2x)×(4x²/9y²)=2x/3y;如果本题有什么不明白可以追问,
(xy-x的平方)÷xy分之x-y=x(y-x)*xy/(x-y)=-x^2y(x的平方+x分之4x的平方-1)乘(1-2x分之x+1)÷x分之1=[x(x+1)分之(2x+1)(2x-1)]乘(1-
x-y分之2x的平方-y-x分之x的平方-4xy+x-y分之2y的平方-x的平方=2x/(x-y)-(x²-4xy)/(y-x)+(2y-x²)/(x-y)=(2x+x²