3(X Y)平方-27(Y-X)平方因式分解-搜答案-大师作文网

x平方+3xy+2y平方/x平方y+2xy平方=（x+2y）（x+y）/x(x+2y)=(x+y)/x在我回答的右上角点击【评价】,然后就可以选择【满意,问题已经完美解决】了.

原式=x²-y²-(4x²y²+12xy²+9y²)=x²-y²-4x²y²-12xy²-

xy(xy+1)+(xy+3)-2(x+y+1/2)-(x+y-1)^2=xy(xy+1)+(xy+1)+2-2(x+y)-1-[(x+y)^2-2(x+y)+1]=(xy+1)^2+2-2(x+y)

=(6x³y²-18x²y³+27x^6y³)/(3x²y²)=6x³y²/(3x²y²)

x²+12xy+27y²=0(x+3y)(x+9y)=0x=-3y或x=-9yx=-3y时,(x²-2xy+2y²)/(3x²-3xy-y²

(3xy)平方/(-xy)+(x-2y)平方-(x+2y)(x-2y)=-9xy+(x-2y)(x-2y-x-2y)=-9xy+(x-2y)(-4y)=-9xy-4xy+8y²=8y

(3x平方-4y平方)+[-(x平方-2xy-y平方)]-[(3x平方-2xy-y平方)]=3x²-4y²-x²+2xy+y²-3x²+2xy+y&#

2x方y和3x方y是同类项,剩下两个是同类项,合并后为5x方y和-3x方y

3x²y+{xy-[3x²y-(4xy²+1/2xy)]-(4x²y+3/2xy)}=3x²y+xy-3x²y+4xy²+1/2x

原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)

=-3x(x^2+2xy+2y^2)

5xy平方-2x平方y+[3xy平方-(4xy-2x平方y-2x平方y)]＝5xy平方-2x平方y+[3xy平方-4xy＋2x平方y＋2x平方y)]＝5xy平方-2x平方y+3xy平方-4xy＋2x平

3x³－12x²y＋12xy²=3x﹙x²－4xy＋4y²﹚=3x﹙x－2y﹚²

-12XY×3X平方Y-X平方Y×（-3XY）=-12×3X^3Y^2-(-3X^3Y^2)=-36X^3Y^2+3X^3Y^2=-33X^3Y^2

x平方+3xy+y平方=x²-2xy+y²+5xy=(x-y)²+5xy=(-3)²+5*9=9+45=54

原式=[(x²+xy)+y²][(x²+xy)+3y²]+y^4=(x²+xy)²+4(x²+xy)y²+3y^4+y^

(2X平方y+3xy平方)-(6x平方-3XY平方)=2x²y+3xy²-6x²+3xy²=2x²y+6xy²-6x²

-12xy*3x^2y-x^2y*(-3xy)=-36x^3y^2+3x^3y^2=33x^3y^2

2x平方y-2xy+3xy平方+5+2xy+x平方y-3xy平方-3=2x²y-2xy+3xy²+5+2xy+x²y-3xy²-3=3x²y+2

（3X平方-5Y）+[-3XY-2(X平方-XY)+Y平方]=3X平方-5Y-3XY-2X平方+2XY+Y平方=X平方-5Y-XY+Y平方再问：谢谢你再答：不客气，采纳我哦