3x y=2k 2y-x=3 满足x1 则k的取值范围为

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3x y=2k 2y-x=3 满足x1 则k的取值范围为
实数x,y满足方程x^2-3xy+3y^2+4x-18y+52=0

x^2+(4-3y)x+3y^2-18y+52=0x=0.5(3y-4+sqrt((4-3y)^2-4(3y^2-18y+52)))=0.5(3y-4+sqrt(-3(y-8)^2))或x=0.5(3

已知正实数x y满足x-根号xy-2y=0求 x+3根号xy+2y/2x-2根号下xy-y

答:x>0,y>0x-√(xy)-2y=0(√x-2√y)(√x+√y)=0因为:x>0,y>0所以:√x+√y>0所以:√x-2√y=0所以:√x=2√y所以:x=4y所以:[x+3√(xy)+2y

已知x和y是整数,满足xy=xy分之6那么2x-3y的值为

xy=6/(x+y)xy(x+y)=6,已知x和y是整数,则xy和(x+y)也是整数,而6=2*3=1*6当xy=3时,x+y=2,无整数解当xy=1时,x+y=6,无整数解当xy=6时,x+y=1,

实数x、y、z满足x=6-3yx+3y-2xy+2z

x=6-3y               &nbs

已知x y都是实数 且满足x^2+y^2+xy=1/3,求xy的最大值

解由题知求xy的最大值,则x,y必定同号,不妨设x,y同正则由x^2+y^2+xy=1/3得1/3=xy+x²+y²即1/3-xy=x²+y²≥2xy即1/3≥

已知实数xy满足x^2+3x+y-3=0 则x+y的最大值为

x²+3x+y-3=0x²+2x+x+y-3=0(x+1)²+x+y-4=0x+y=4-(x+1)²因为要使x+y最大,所以(x+1)²一定要取最小值

设xy满足约束条件 x+y>=1 x-2y>=-2 3x-2y

x,y取值范围如上图,凸点为:(0,1)   (1,0)   (2.5, 2.25)目标函数在凸点的取值:4,1,26.5∴z的取

不好意思,已知有理数x、y满足x=|y|,|xy|+xy=0,化简|y|+|-2x|-|3y-2x|=?

由x=|y|得x为非负数又|xy|+xy=0所以xy为非正数y为非正数所以原式=(-y)+2x-[-(3y-2x)](最后一步3y是非正数,2x是非负数,2x一定大于或等于3y,故加负号)=-y+2x

若方程组2x+y=2k2y−x=3

解方程组2x+y=2k2y−x=3得:x=4k−35y=2k+65因为x<1,y>1,所以4k−35<12k+65>1,解得-12<k<2,所以k为0或1.即,整数k的个数有2个.

先化简再求值3(2x^2y-xy^2)-(5x^2-4xy^2)其中x y 满足|x+2|+(y-1/2)=0

若|x+2|+(y-1/2)平方=0,则有:x+2=0且y-1/2=0解得:x=-2,y=1/2所以:3(2x^2y-xy^2)-(5x^2y-4xy^2)这里是不是少打了个y哈!=6x平方y-3xy

已知方程组x-2y=3m-2,x+y=10的解x、y满足xy

x-2y=3m-2x+y=10y=4-mx=m+6xy4或m

已知实数x、y满足2x2-7xy+3y2=0,求x:y

分解因式有(x-3y)(2x-y)=0所以有x=3y或2x=y所以x:y=3:1或x:y=1:2

已知A=3x²-xy+y²,B=2x²-3xy-2y²,其中x、y满足等式2(x

因为2(x-1/2)²+|y-1|=0所以x-1/2=0且y-1=0x=1/2,y=1所以3B-2A=3(2x²-3xy-2y²)-2(3x²-xy+y

若两个正实数x,y满足x^2+2xy-3y^2=0,求x^2+xy+y^2/x^2-xy+y^2

x^2+2xy-3y^2=0x^2+2xy+y^2-4y^2=0(x+y)^2=4y^2x+y=2y或x+y=-2yx=y或x=-3y因为两个正实数所以x=yx^2+xy+y^2/x^2-xy+y^2

若x,y满足y=根号2x-3+根号3-2x+6,求xy的平方根?

2x-3>=03-2x>=0∴x=3/2把x=3/2代入y=根号2x-3+根号3-2x+6得y=6∴xy=9xy的平方根是±3

先化简再求值(-2xy+2x+3y)-(3xy+2x-2y)-(x+4y-xy),其中x、y满足x-y=10,xy=-4

(-2xy+2x+3y)-(3xy+2x-2y)-(x+4y-xy)=-2xy+2x+3y-3xy-2x+2y-x-4y+xy=-4xy-x+y=-4xy-(x-y)=-4×(-4)-10=6

若实数x,y满足1/x-1/y=5,则分式3x-2xy-3y/x+xy-y的值等于?

1/x-1/y=5即,(y-x)/xy=5即,x-y=-5xy(3x-2xy-3y)/(x+xy-y)=[3(x-y)-2xy]/[(x-y)+xy]=(-15xy-2xy)/(-5xy+xy)=(-

已知XY的方程组{4x-3y=k 2x+3y=5}的解满足x

4x-3y=k①2x+3y=5②①-②×2得:4x-3y-4x-6y=k-10-9y=k-10y=-(k-10)/9①+②得:4x-3y+2x+3y=k+56x=k+5x=(k+5)/6因为x

先化简,再求值 :(xy-3x^2)-2(xy-2x^2-1),其中x、y满足条件丨x+2丨+(y-1)^2=0

丨x+2丨+(y-1)^2=0丨x+2丨=0,(y-1)^2=0x+2=0,y-1=0x=-2,y=1所以(xy-3x^2)-2(xy-2x^2-1)=(xy-3x^2)-2xy+4x^2+2=-xy