3X-5=2x(2X-4)方程的解-搜答案-大师作文网

乘出来3x³+5x²+5=-x³+4x³+5x²+x3x³+5x²+5=3x³+5x²+x两边减去3x

(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么

((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30

4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~

x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1

是方程叫恒等式方程X的解是所有实数

原式5/X（X-2）-4/X（X+2）=3/X²-45（X+2）/X(X-2)(X+2)-4(X-2)/X(X-2)(X+2)=3/X²-4(5X+10)/X-(4X-8)/X=3

(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)

再问：2x是怎么得来的

2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99

x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)

x(2x-3)+3x+3x(x-2)=5x(x-4)+112x²-3x+3x+3x²-6x=5x²-20x+115x²-6x=5x²-20x+115x

方程3+2x=5x

3+2x=5x5x-2x=33x=3x=1

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(

(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1

2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11

(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1

由题意知：X不等于0方程可化为4/(X^2+2X+1)+5/(X^2+2X-5)+3/2=0设X^2+2X=Y则:4/(Y+1)+5/(Y-5)+3/2=0然后通分:Y^2-2Y-15=0所以Y=5O

解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2