因式计算:x平方-y平方-ax ay
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原式=(x+y)(x-y)/(x-y)^2=(x+y)/(x-y)=120/100=1.2^2指平方
x^2/25-y^2/16=(x/5-y/4((x/5+y/4)16x^2+4x+0.25=16x^2+4x+1/4=(4x+1/2)^2
(x+y)^2-(x-y)^2={(x+y)+(x-y)}{(x+y)-(x-y)}=2x*2y=4xy
=[5(x+y)]²-[4(x-y)]²=(5x+5y+4x-4y)(5x+5y-4x+4y)=(9x+y)(x+9y)
12m(x+y)的3次方-9n(x+y)的平方=3(x+y)²(4mx+4my-3n)如果本题有什么不明白可以追问,
1x²+2xy-3y²=x²+2xy+y²-4y²=(x+y)²-(2y)²=(x+y+2y)(x+y-2y)=(x+3y)(x-
=7x²-4x²+4xy-y²=7x²-(2x-y)²=(√7x+2x-y)(√7x-2x+y)本题答案不唯一的
^3代表3次方,^2代表平方X^3+X^2-Y^3-Y^2=(x^3-y^3)+(x^2-y^2)=(x-y)(x^2+xy+y^2)+(x-y)(x+y)=(x-y)(x^2+xy+y^2+x+y)
=x^3-y^3-(x^3+y^3)=-2y^3^3表示三次方
把x+y当做一个因子,7当做一个因子(x+y)^2-14(x+y)+49=(x+y)^2-2*7*(x+y)+7^2=(x+y-7)^2
题目有问题吧,我感觉应该是(x²+y²-z²)²-4x²y²(x²+y²-z²)²-4x²
(x+y)^3-y(x+y)^2+x^2(y+x)=(x+y)[(x+y)^2-y(x+y)+x^2]=(x+y)(x^2+2xy+y^2-xy-y^2+x^2)=(x+y)(2x^2+xy)=x(x
(x-y)^2-(y-x)^3=(x-y)^2+(x-y)^3=(x-y)^2(x-y+1)
(x+3y)(x-y)
=[(x+y)-2y]²=(x-y)²
x²-4y²=x²-(2y)²=(x+2y)(x-2y)这里用到了平方差公式.很高兴为您解答,祝你学习进步!如果我的回答对你有帮助,请及时选为满意答案,谢谢~~
(x^2+4y^2)^2-16x^2y^2=(x+4y)-(4xy)=(x+4y+4xy)(x+4y-4xy)=(x+2y)(x-2y)请采纳回答
16(X+Y)平方-9(Y-X)平方=[4(x+y)]²-[3(y-x)]²=[4x+4y-3y+3x][4x+4y+3y-3x]=(7x+y)(x+7y)
(x+y)的平方-6x的平方+6y的平方+9(x-y)的平方=(x+y)²-6(x²-y²)+9(x-y)²=(x+y)²-6(x+y)(x-y)+9
x^2-y^2+ax+ay=(x+y)(x-y)+a(x+y)=(x+y)(x-y+a)