在主函数中通过调用该函数实现三个数由小到大的顺序输出.

#includedoublefun(doublex,doubley){returnx*x*x+y*y*y;}voidmain(){doublea=fun(3.4,2.8);doubleb=fun(10

#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fact(n-1);}voidmain(){for(inti=2;i

Bigger(inta,intb){returna>b?a:b;}Biggest(inta,intb,intc){returnBigger(a,b)>c:Bigger(a,b):c;}

#includeusingnamespacestd;floatmianji(floata,floatb){returna*b;}floatzhouchang(floata,floatb){return

用VB做：建立三个TEXT文本框,分别为上底,下底,高,再建立一个COMMAND和一个TEXT4,TEXT用于存放计算结果.OMMAND建立事件CLICK.TEXT4.TEXT=(TEXT1.TEXT

#include#includeintmax(inta,intb){if(a>b)returna;if(a

#includeintprime(intn){if(n

#includevoidshow();voidmain(){show();}voidshow(){printf("Ilovechina!");}

#includeintfun(intn){\x09ints=1,i;\x09for(i=1;i

如果需要n是变量,则使用指针,以下是原地转置voidTrans(int*a,intn){inttemp,i,j;for(i=0;ifor(j=0;j{temp=a[i*n+j];a[i*n+j]=a[

==||童鞋.你是要返回输入的n个数的最大值,还是一个数组的最大值啊.返回输入n个数最大值的函数：#includeintMax(intn);//最大值函数声明intmain(){intn;scanf(

我用C语言编一下啊.其他语言类似!#includevoidsort(intn){if(n%2==0)printf("thenumberisdouble\n");elseprintf("thenumbe

#includefloatmax(floata,floatb){if(a>b)returna;returnb;}voidmain(){floata,b,c,d;scanf("%f,%f,%f",&a,

#include"stdio.h"longintcal(longinta){for(longinti=1,sum=1;i

#include#includeboolisPrime(intnum){if(num!=2&&num%2==0)//除2以外的偶数都不是素数{returnfalse;}for(inti=3;i

#include#includevoidb1(){floatl,s,k;inta,b,c,h;printf("\n");printf("\n");printf("输入a,b,c的值\n");print

#includefloatfun(floatC){floatF;F=C*9/5+32;returnF;}voidmain(){floatC,F;printf("输入摄氏温度:");scanf("%f"

java版实现public class Calculator{    public int calTest(int&nb

#includeusingnamespacestd;inlineintsquare(intx){returnx*x;}intmain(){intsum=0;for(inti=1;i

这个题目应当有原来的程序,让人填空.如果自己写程序,很简单：#include#includevoidfun(int*x,int*y){intz;z=*x;*x=*y;*y=z;}main(){inta