在化简(x y)(x-2y)(m,n均为常数)
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x^2+2xy+y^2/x^2-y^2除以x^2+xy/xy-y^2=(x+y)²/(x+y)(x-y)÷x(x+y)/y(x-y)=(x+y)/(x-y)×y(x-y)/x(x+y)=y/
(x-2)²+∣y-3∣=0(x-2)²=0,∣y-3∣=0x=2y=3(x-y)/(x²-2xy+y²)-(xy+y²)/(x²-y
x=2+m/3;y=2m/3-2∵xy小于0∴(6+m)×(2m-6)<0-6<m<3又∵x、y都为整数∴m为3的整数倍,所以m为-3,0
3x²y-[2xy²-2(xy-3/2x²y)+xy]+3xy²=3x²y-2xy²+2xy-3x²y-xy+3xy²=
xy-2{xy-[3x²y-(xy²+0.5xy)]+4x²y}=xy-2[xy-(3x²y-xy²-0.5xy)+4x²y]=xy-2(x
(x+y)^2/xy-(x-y)^2/xy=【(x+y)^2-(x-y)^2】/xy=(x²+y²+2xy-x²-y²+2xy)/xy=4xy/xy=4很高兴为
化简求值:(x+y)(x-y)-(x-y)²-6x²y÷2y+(2xy)²÷(-4xy)=(x-y)²-(x-y)²-3x²-1/2y=-3
解3x²y-[2xy-2(xy-3/2x²y)+xy]+3xy²=3x²y-(2xy-2xy+3x²y+xy)+3xy²=3x²y
2x^2y+[2xy-[3x^2y-2[2xy-3xy^2]]-4xy^2]=2x^2y+[2xy-[3x^2y-4xy+6xy^2]-4xy^2]=2x^2y+[2xy-3x^2y+4xy-6xy^
(xy-x²)÷(x²-2xy+y²)/(x-y)×(x-y)/x²=-x(x-y)÷(x-y)²/x²=-x(x-y)×x²/(
急不解决问题最后还是靠自己多动脑看课本其实都是课本上的再问:你看看啊!课本上没有,不会才问的!.........
M=(2x^2y+xy^2)(x-2y)-(2x^2-3xy+xy^2)(-xy)很简单啊.
(1)X+Y=M(2)2X-Y=6(1)+(2)3X=M+6X=(M+6)/3=M/3+2Y=2X-6=(2M-6)/3=2M/3-2XY是整数所以M是3的倍数XY
(x+y)(x-y)-(x-y)²-6x²y/2y+(2xy)²/(-4xy)=x²-y²-x²+2xy-y²-3x²-
原式=(x^2-y^2-x^2-2xy-y^2-2xy+2y^2-2xy)/xy=(-6xy)/xy=-6
-5y²+{2xy-[y²+x²-(1-y²)+2xy]+3x²}=-5y²+{2xy-y²-x²+(1-y²
x>0;y>0积3>=(6xy)^0.5=>9>=6xy=>1.5>=xy=>max(xy)=1.5...ans此时2x=3y=3;x=1.5,y=1
相加得X=(M+6)/3,相减得Y=(2M-6)/3,XY=(2M^2+6M-36)/9
5xy^2-[3xy^2-(4xy^2-2x^y)]+x^2y-xy^2=5xy^2-3xy^2+(4xy^2-2x^y)+x^2y-xy^2=5xy^2-3xy^2+4xy^2-2x^y+x^2y-
3(1,4)和0(2,2)