4x加6y=5 x-3y=2 这么解

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4x加6y=5 x-3y=2 这么解
x+y/2+x-y/3=6,4(x+y)-5(x-y)=2用加减消元法解方程组

1,x+y/2+x-y/3=6即:5x-y=36①4(x+y)-5(x-y)=2即:-x+9y=2②①+②*5==可接2,先化整:3(x+y)+2(x-y)=36①4(x+y)-5(x-y)=2②①*

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20

由(1)得3x+3y+2x-2y=365x+y=36(3)由(2)得4x+4y-3x+3y=-20x+7y=-20(4)(3)×7-(4)得34x=272∴x=8把x=8代入(3)得y=-4∴x=8y

1.若x+2y分之2x-y=5,求代数式(x+2y分之12x-6y减去2x-y分之x+2y)加3的值

1.33又五分之一2.213.13分之124.a=_-3___时,它有最大值为_3___

已知x.y为实数,y=根号x^2-4 加根号 4-x^2 加一/x-2,求:3x加4y

由于√x²-4与√4-x²都要成立则x²-4=0所以x=2或者-2由于1/x-2成立则x≠2所以x=-2y=1/(-2-2)=-1/4所以3x+4y=3*(-2)+4*(

{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20

{(x+y)/2+(x-y)/3=63(x+y)+2(x-y)=36(1)4(x+y)-3(x-y)=-20(2)由(1)*3+(2)*2得9(x+y)+6(x-y)+8(x+y)-6(x-y)=36

3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27

化简得:-x+7y=11①7x+3y=27②①式×7得:-7x+49y=77③②+③得:52y=104∴y=2代入①得:x=3∴x=3,y=2再问:亲,是代入法哦!再答:代入法①式得3x+3y-4x+

3x+4y=16 5x-6y=33 这么做?

5*(3X+4Y)=3*(5X-6Y)=为了消元,把x消掉,(1)×5,(2)x3目的是让x系数一样,做差消掉

第一题.4(X+Y)减去3(x减去y)=14 2分之x加y加3分之x减去y等于6

4(x+y)-3(x-y)=14x+7y=14(x+y)/2+(x-y)/3=6两边同乘以6,得3(x+y)+2(x-y)=365x+y=36则x+7(36-5x)=14x=7,y=1

解方程组:2分之2x+y加3分之2x-y=1,4*(2x+y)-5(2x-y)=8,

2分之2x+y加3分之2x-y=1,——》10x+y=6,.(1)4*(2x+y)-5(2x-y)=8,——》9y-2x=8,.(2)(1)+(2)*5,得:46y=46,即y=1,代入(1),得:x

若实数X,Y满足X的2次方加4Y的2次方加4X加4Y加5=0.求X,Y

x^2+16y^2+4x+4y+5=0x^2+4x+4+4y^2+4y+1=0(x+2)^2+(2y+1)^2=0因为x^2>=0所以x+2=02y+1=0所以x=-2y=-1/2

若5x+3y=3x+4y=x+2y+6,则x+y=___

3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3

4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6

第二个方程是不是写错了2/(x+y)+3/(x-y)=6是这样吗

解方程组 {(x+y)/2+(x-y)/3=6 5(x+y)-2(x-y)=4

(x+y)/2+(x-y)/3=6①5(x+y)-2(x-y)=4②由①得3x+3y+2x-2y=365x+y=36y=36-5x③由②得5x+5y-2x+2y=43x+7y=4④③代入④得3x+25

解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12

设a=x+y,b=x-y原方程组为:a/2+b/3=6,即3a+2b=36,即:12a+8b=1444a-5b=12,即:12a-15b=36相减得:23b=108,得:b=108/23,再得:a=1

解方程组 X+Y/2+X-Y/3=6 4[X+Y]-5[X-Y]=2

先将第一个等式整理得12X+Y=36,第二个等式整理得-X+9Y=2,由第一个等式得Y=36-12X,通过换元法得-X+9(36-12X)=2,解出X=322/109,再把X=322/109代入-X+

4x-2y-6y*-y-3x+5y* *=2 就是平方

题意不清什么是平方,*吗?那么**代表三次方还是4次方呢

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

解二元一次方程2分之X+Y加三分之X—Y等于6 4(X+Y)—3(X—Y)=--20

题目是这样的:(X+Y)/2+(X-Y)/3=6(1)4(X+Y)-3(X-Y)=-20(2)将(1)两边同时乘以6得3X+3Y+2X-2Y=36→5X+Y=36(3)将(2)化解为4X+4Y-3X+

已知X,Y为实数,且X=根号1-3Y加根号3Y-1加2,求6Y-4X的直

依题意可知在根号下的1-3y和3y-1都有意义故1-3y〉=0且3y-1〉=0所以y=1/3x=26y-4x=-6