多项式5 2x^3y-3y^3-x^2 xy^2按x的降幂排列是
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/23 16:33:04
原式=[(a-2)x^2]+(b+2)y-7(合并同类项)因为无论x,y取任何数,该多项式的值都不变,所以a=2,b=-2.所以4(a²-ab+b²)-3(2a²+b
因为代数式x*-3x+2-(y-3)/x是关于x的多项式,所以-(y-3)/x=0,所以y=3,所以y^2+2y+1=3^2+2*3+1=16.
(x-3)(y+2)=xy-3y+2x-6=xy推出2x-3y=6(x+1)(y-1)=xy-x+y-1=xy-6推出x-y=5解方程组,得:x=9;y=4.同学,要动脑哇!
(x-y)(x+y-1)(x+y)^2y(x+6)(x-2)
差是:(3x+2y)-(4x-2y)=3x+2y-4x+2y=-x+4y
5(x-y)²-(x-y)-8(x-y)²-3(x-y)=[5(x-y)²-8(x-y)²]-[(x-y)+3(x-y)]=-3(x-y)²-4(x-
若将x-y看成一个整体,合并多项式(x-y)+3(x-y)-2(y-x),可得6(x-y)
(3x-y)(y+3x)-(4x-3y)(4x+3y)=(3x-y)(3x+y)-(4x-3y)(4x+3y)=(9x²-y²)-(16x²-9y²)=9x
X-Y看成一个整数,合并多项式(X-Y)²+3(X-Y)-2(Y-X),可得?(X-Y)²+3(X-Y)-2(Y-X),=(X-Y)²+3(X-Y)+2(x-y),=(X
[21x^5y^7+y(7x^3y^2)^2]/[-7x^5y^4]=21x^5y^7/[-7x^5y^4]+y(7x^3y^2)^2/[-7x^5y^4]=-3y^3+7x^6y^5/[-7x^5y
(3x-2y)-(4x-2y)=3x-2y-4x+2y=-x
(x-y)2+3(x-y)-2(y-x)=2(x-y)+3(x-y)+2(x-y)=7(x-y)
3x-2y-(4x-2y)=3x-2y-4x+2y=-x
(1)-xy²+2x²y+3x³-4y³=3x³+2x²y-xy²-4y³(2)-xy²+2x²y+
1、项数=2010项,次数=2009次2、第100项:-x^1910y^99;第101项:x^1909y^100,按照y的次数写就可以了3、x=1,y=-1原式=1+1+1+……+1=2010
(x^3-3x^y+3xy^2-y^3)-(x^3+3x^y+3xy^2+y^3)=x^3-3x^y+3xy^2-y^3-x^3-3x^y-3xy^2-y^3=-6x^y-2y^3
由题意得:差=3x+2y-(4x-2y),=-x+4y.故填:-x+4y.
应该是(-y^3+3y^2+y)-(-2x^3+x^2+2x),其中被减式-y^3+3y^2+y,减式-2x^3+x^2+2x.
解2x³-3xy-y²+(x³+xy+y²)=(2x³+x³)+(xy-3xy)+(y²-y²)=3x³-2x