6x-2分之1=0.5怎么解方程

若X方-2XY+Y方+1XY-11=0则：x-y=0.而且xy=1所以,x=y=1,或者,x=y=-1所以,x/y=1X方+6XY+9Y方分之X方-25Y方*5X-25Y分之X+3Y=（x²

(x+1)/x²-2x²/(x+1)=1设(x+1)/x²=t,则方程变为：t-2/t=1,即：t²-t-2=0,即(t-2)(t+1)=0∴t1=2t2=-1

x²-7/x+x²-3/x=x²-6?是这样么再问：有详细的吗再答：我是为你的题目就是这样么？？你方程两边同时乘以x（x+1）（x-1）得到；7x-7+3x+3=6x;4

f(1/x)=1-x^2+1/x^2=-f(x)直接代入即可再问：能写的再具体点吗我不太明白谢谢再答：哦我把题目看错了你的题目是对的吗再问：嗯题目是对的加我Q1047763981这样说方便再答：我没有

第一个化简就x^2+x-6=x=-3或x=2第二个没有看懂.看成5倍X方-3X-1化简为2*x^2-6*x-4-5*√（x^2-3*x-1）-3=0令y=√（x^2-3*x-1）原方程化为2*y^2-

x/(1-x)+x/(1+x)+2x/(1+x^2)+4x/(1+x^4)=0[x(1+x)+x(1-x)]/(1-x^2)+2x/(1+x^2)+4x/(1+x^4)=02x/(1-x^2)+2x/

1,去分母,等号两边同时乘以3x+33x=2x+12（3x+3）去括号移项,合并同类项,系数化为12.等号左右同乘x方-12（x+1）=4x=1,检验x=1时,方程分母为0,所以x=1是方程的增根,方

两边乘(x+2)(x-2)2(x+2)=1x=-3/2分式方程要检验经检验,x=-3/2是方程的解

饿X方可以表示为X^2首先通分把方程变为X^2-6X+8=-1X^2-6X+9=0（X-3）（X-3）=0很明显了吧X=3

(x-2)/(x+2)-1=3/(x²-4)[(x-2)-(x+2)]/(x+2)=3/[(x-2)(x+2)]-4/(x+2)=3/[(x-2)(x+2)]-4(x-2)=3x=-5/4代

x+3分之2+2分之3=2x+6分之7两边乘以2(x+3)得4+3(x+3)=74+3x+9=73x=-6∴x=-2经检验：x=-2是方程的根（x方-1分之x方-4x）+1=x+1分之2x两边乘以(x

x^2-9=(x^2-6x+9)/22(x^2-9)=(x^2-6x+9)2(x-3)(x+3)-(x^2-6x+9)=02(x-3)(x+3)-(x-3)^2=0(x-3)[2(x+3)-(x-3)

把每个式子因式分解x的方+5x+4=（x+1）(x+4)x方-5x+6=(x-2)(x-3)………………

2/3x^2=1-4x3x^2=2-8x3x^2+8x-2=0用公式法x=（-4+根号22）/3或者x=（-4-根号22）/3

=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+

(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x

x+1分之2+x-1分之3=x二次方-1分之6两边乘以(x²-1)得2x-2+3x+3=65x=6-1=5x=1又因为原方程x二次方-1是分母≠0x=1不满足要求方程无解

 再答：求采纳

6已知x+y=2,x-y=1,求分式x方+2xy+y方分之x方-y方的值x方+2xy+y方分之x方-y方=(x+y)(x-y)/(x+y)²=(x-y)/(x+y)=1/27已知x分之1-y

2x^2-x+(1/16)=0==>x={-(-1)±√[(-1)^2-4*2*(1/16)]}/(2*2)==>x={1±√[1-(1/2)]}/4==>x=[1±√(1/2)]/4==>x=[1±