1 x-1 y=3 3x-2xy-3y x xy-y=

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1 x-1 y=3 3x-2xy-3y x xy-y=
计算3xy[2xy-x(y-2)+x-1]

3xy[2xy-x(y-2)+x-1]=3xy(2xy-xy+2x+x-1)=3xy(xy+3x-1)=3x^2y^2+9x^2y-3xy

(1)已知x+y=6,xy=-3,x^2y+xy^2=

(1)已知x+y=6,xy=-3x^2y+xy^2=xy(x+y)=-3*6=-18(2)x*[2-(1/x)]+(x/x^2-2x)*(x^2-4)=x*(2x-1)/x+[x/x(x-2)]*(x

已知:x-y=1,xy=-2.求:(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-6xy+3x-3y=-6×(-2)+3×1=15

-3xy(x^2-2x-1)+(2x-3y)(3x-4y)=?

-3xy(x^2-2x-1)+(2x-3y)(3x-4y)=-3x^3y+6x^2y+3xy+6x^2-8xy-9xy+12y^2=-3x^3y+6x^2y+6x^2-14xy+12y^2

已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y)

3/(x-y)=1/xyx-y=3xyy-z=-3xy原式=[(y-x)-2xy]/[2(x-y)+3xy]=[(-3xy)-2xy]/[2(3xy)+3xy]=-5xy/9xy=-5/9

若x-y=4,xy=1,求(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6xy+3*(x-y)当时,原式=-6*1+3*

(x+2y-3xy+2x+y-xy)-(-2-y+xy),其中x+y=2分之1,xy=-2分之1

(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2

5xy平方-2x平方y+[3xy平方-(4xy-2x平方y-2x平方y)],其中x=-2,y=-1求值

5xy平方-2x平方y+[3xy平方-(4xy-2x平方y-2x平方y)]=5xy平方-2x平方y+[3xy平方-4xy+2x平方y+2x平方y)]=5xy平方-2x平方y+3xy平方-4xy+2x平

(x+2y-3xy)-(-2x-y+xy),其中x+y=1/2,xy=-1/2

(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2

[3xy(1-x)-6xy(x-1/2)]*2x*(-xy)平方,x=-1 y=2 ; 3xy平方(-1/3x平方y+4

[3xy(1-x)-6xy(x-1/2)]*2x*(-xy)平方=(3xy-3x²y-6x²y+3xy)(2x³y²)=12x^4y³-18x^5y&

xy/3x+2y=1/8 xy/2x+3y=1/7

设X=kY.kY^2/(3k+2)Y=1/8kY^2/((2k+3)Y=1/7由上式得:3k+2=8kY,2k+3=7kY所以2/(8Y-3)=3/(7Y-2)所以Y=1/2,X=1

已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=

因为xy/(x+y)=1/2所以x+y=2xy原式=3(x+y)-5xy/(-x-y+3xy)=3*2xy-5xy/(-2xy+3xy)=xy/xy=1

x(x-1)-(x平方-y)=-3,求x平方+y平方-2xy

x{x-1}-{x^2-y}=-3即x^2-x-x^2+y=-3-x+y=-3x-y=3而x^2+y^2-2xy=(x-y)^2=3^2=9

已知x-y=3,xy=1,求(-2x+2x+3y)-(3xy+2y-2x)-(x+4y+xy)

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=(-2xy-3xy-xy)+(2x+2x-x)+(3y-2y-4y)=-6xy+3x-3y=-6+3*3=3

1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y)

1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)

若x=1/2,y=1 求x(x²+xy+y²)-y(x²+xy+y²)+3xy(

x(x²+xy+y²)-y(x²+xy+y²)+3xy(y-x)=X^3+X^2Y+XY^2-X^2Y-XY^2-Y^3+3XY^2-3X^2Y=X^3-3X^

-3(2x-xy)-4(-6+xy+x.其中x=1,y=-1

-3(2x-xy)-4(-6+xy+x)=-6x+3xy+24-4xy-4x=-10x-xy+24=-10+1+24=15先化简.后代入求值

.已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值

(-2xy+2x+3y)-(3xy+2y-2x)-(x+4y+xy)=-2xy+2x+3y-3xy-2y+2x-x-4y-xy=-6xy+3x-3y=-6*(-2)+3*1=15不懂可追问,有帮助请采