将一个数组逆序输出.例如,原来是8,6,5,4,1,要求改为1,4,5,6,8.
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/23 16:19:10
#includevoidmain(){inti;printf("pleaseinputanumberbetween0and1000:");scanf("%d",&i);if(i>1000||i=100
stringa=Conlose.ReadLine();inti=.length;stringnewStr="";while(i>0){i--;newStr+=a[i].toString();}Cons
intmain(void){\x05intn;\x05intcount=0;\x05inta,b,c,d,e;\x05printf("请输入一个不低於5位的正整数:");\x05scanf("%d",
#includemain(){inta[5],i,temp;/*定义数组及变量为基本整型*/printf("pleaseinputarraya:\n");for(i=0;iscanf("%d",&a[
#includemain(){inti,b[10];for(i=0;i-1;i--)printf("%5d",b[i]);printf("\n");}再问:5、输入年月日,输出这一天是本年度的第几天。
#include"stdio.h"voidmain(){\x09inta;\x09intb[3];\x09intcount=0;\x09printf("请输入一个数");\x09scanf("%d",
算法分析:把输入的三位数分解(百,十,个);再交换个位和百位就可行了.#include{intn,a,b,c,x;printf("请输入一个三位数:\n");scanf("%d",&n);a=n/10
intmain(){intn,n1,n2;cin>>n1;n2=n1%100;n1=n1/100;n=n1;n2=n2%10;n1=n1/10;n=n+10*n1+100*n2;returnn;}
#include"stdio.h"intmain(){inti,j,a[3][4];for(i=0;i
#include"stdio.h"main(){chara[10];inti,j;h:printf("请输入数字,注意不能超过5位:");gets(a);for(i=0;a[i];i++);if(i>
#includevoidreverse(inta[],intn){int*p=a+n-1;intt;while(a
importjava.util.Scanner;publicclassQk{publicstaticvoidmain(String[]args){inti;System.out.println("请指
#includeint*ReverseArray(int*orig,unsignedshortintb){unsignedshortinta=0;intswap;for(a;a
JavapublicclassSortAry{publicstaticvoidmain(String[]args){intary[]={8,6,5,4,1};int[]newAry=newint[ar
在这组《趣味数独》的每一行、每一列都由9个数字组成,请大家在空格里填上1到9的不同数字.每一行、每一列的数字都是由1到9组成,不能重复.7()938()()()4()1()7()()()()()()(
-----以下是JavaScript:------------a=newArray(8,6,5,4,1);alert(a.reverse());//反转数组的内容.C语言:inta=[8,6,5,4,
publicclassTest1{\x09publicstaticvoidmain(String[]args){\x09\x09Strings="Iamastudent";\x09\x09Test1t
#includevoidinput(inta[],intn)//输入{inti;printf("请输入%d个数,用空格隔开\n",n);for(i=0;i
#include#defineNUM20voidmain(){longn;intdata[NUM]={0},len=0;scanf("%d",&n);do{data[len++]=n%10;n/=10