1-2XY的平方 X的平方*Y的四次方
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解xy²-2xy-y²+x+2y-1=xy²-2xy+x-y²+2y-1=x(y²-2y+1)-(y²-2y+1)=(x-1)(y-1)
(x的平方+2xy+y的平方)(x的平方-xy+y的平方)的平方=(x²+2xy+y²)(x²-xy+y²)²=(x+y)²(x²
1、原式=[2x/(x^2-1)]-[(x+1)/(x^2-1)]=[2x-(x+1)]/(x^2-1)=(x-1)/(x^2-1)=(x-1)/[(x+1)(x-1)]=1/(x+1)2、原式=[x
y/(x²-xy)+2/(y-x)-x/(y²-xy)=[y²+2(-xy)+x²]/(x²y-xy²)=(x-y)²/[(x-y
Y^2(2X+1)(X-3)
楼主是不是把题写错了呀,应该是(X+2)^2+/Y+1/=0吧因为(X+2)^2大于等于0/Y+1/大于等于0所以只有同时为0时,和才为0即X=-2Y=-1带入原式=4
是3x²y-3xy²+2x²y+2xy²-1=5x²y-xy²-1
2xy/(y^2/x)=2xy÷(y^2/x)=2xy×(x/y^2)=2x^2/y再问:O(∩_∩)O谢谢
已知:x²+xy=2,y²+xy=51/2x²+xy+1/2y²=1/2(x²+2xy+y²)=1/2(x²+xy+y²
两式子相加相减得(X+Y)的平方=16X方-Y方=12题一解为4题二解为4
((x-y)(x-y))/((x-y)(x+y))=(x-y)/(x+y).
原式=x²y²+x²y+y²+y+2x²y²+2xy+x=3x²y²+x²y+y²+y+2xy+x再
x的平方-2xy/xy-2y的平方=x(x-2y)/y(x-2y)=x/y
(1)因为x^2+xy=2,y^2+xy=7所以x^2+2xy+y^2=(x^2+xy)+(y^2+xy)=2+7=9(2)因为a^2-ab=3,b^2+ab=2所以a^2+b^2=(a^2-ab)+
|Y-2|+(X-1)平方=0而|Y-2|>=0;(X-1)平方>=0所以只能等于0,即y=2,x=1x立方-x平方y+xy平方+x平方y-xy平方-y立方=1-2+4+2-4-8=-7
原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)
解2xy×(-x²y)=-2x³y²a³b²/3×(-3ab²/2)²——这个吗=a³b²/3×(9a
a(x²+2xy+y²)-b(x²-y²)=a(x+y)²-b(x+y)(x-y)=(x+y)(ax+ay-bx+by)再问:你确定对吗?和我已开始算
5x²+5xy+y²+2x+1=04x²+y²+4xy+2x+x²+1=0(2x+y)²+(x+1)²=0得{2x+y=0---①
(x平方+2xy+y的平方)/(x+y)=(x+y)²/(x+y)=x+y