9xy²-15x³y

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9xy²-15x³y
已知x-xy=8,xy-y=-9,求x+y-2xy的值

x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17

因式分解:x³-5x²y-24xy²

解题思路:提取公因式进行分解解题过程:附件最终答案:略

x²/xy-x/y

求数学达人来解答x²/xy-x/y=(1-x)/y3x/4x+y-x-2y/4x+y=(3x-x-2y)/(4x+y)(1-y/y+x)÷x/y²-x²=(1-y)*(y

x²-6xy+9y²???因式分解

解题思路:本题主要利用完全平方公式进行因式分解即可求出结果解题过程:解:x²-6xy+9y²=(x-3y)2

(xy-x^2)乘以(xy)/(x-y)

对.前提是x不等于y

x*-2xy+3y*=9 4x*-5xy+6y*=30

Solution:x^2-2xy+3y^2=9(1)4x^2-5xy+6y^2=30(2)Eq(1)*5-Eq(2)*2,wehavex^2-y^2=5(3)Eq(2)-Eq(1),wegetx^2+

xy-1+x-y

xy-1+x-y=XY+X-Y-1(加法交换律)=(XY+X)-(Y+1)=X(Y+1)-(Y+1)(提取公因式X)=(Y+1)(X-1)(提取公因式Y+1)这样可以么?

计算:(xy-x²)×x-y/xy

这题少括号了吧.

{xy\x+y=6 xy\9x+4y=1

6x+6y=9x+4y3x-2y=0……1式6x+6y=xy……2式2式-1式乘以2得10y=xyx=10y=15请及时采纳

已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=?

1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因

已知x^2-xy=4,y^2-xy=9,求代数式x^2-2xy+y^2

把已知两式相加结果为13

2x^2-xy-15y^2

2x^2-xy-15y^2=2x²-6xy+5xy-15y²=2x(x-3y)+5y(x-3y)=(x-3y)(2x+5y)2x^2-5x-12=2x²-8x+3x-12

xy=9,x-y=-3,则x平方+3xy+y平方=?

x平方+3xy+y平方=x²-2xy+y²+5xy=(x-y)²+5xy=(-3)²+5*9=9+45=54

化简:x-y/x+3y÷x^-y^2/x^2+6xy+9y^2-(xy/x+y)

[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/

6x^2y^2+xy-15

6x²y²+xy-15=(2xy-3)(3xy+5)

xy=(x-10)(y+1) xy=(x-15)(y+3) 解方程组.

因为:xy=(x-10)(y+1)→xy=xy+x-10y-10①xy=(x-15)(y+3)→xy=+3x-15y-45②由①、②得:x=10y+10③x=5y+15④将③‐­④得:10y+

(x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)

原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&

已知x-y=3xy,且xy不等于0,则-3x+6xy+3y/(7x-5y)-9xy-(3x-y)

因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-

计算4x方-4xy+y方-4x+2y-15 4x方y方-5x方y方-9y方

4x方-4xy+y方-4x+2y-15=(2x-y)^2-2(2x-y)-15=(2x-y-5)*(2x-y+3)4x方y方-5x方y方-9y方题目弄错了吧,应该是这样的吧=4x^2y^2-5xy-9