9[x-8]=5.4wunianji
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设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
再问:额、不懂再答: 再答:后面的看做一个整体再问:好的吧、谢谢大神再答:回来的话,请采纳再问:啊、突然明白了呢。。。
[1-1/(x-4)]+[1-1/(x-8)]=[1-1/(x-7)]+[1-1/(x-5)]1/(x-4)+1/(x-8)=1/(x-7)+1/(x-5)(x-4+x-8)/(x-4)(x-8)=(
13.2x+9x=33.322.2x=33.3x=1.58x-3x=1055x=105x=215.4x+x=12.86.4x=12.8x=2x-0.36x=160.64x=16x=25
(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(x+
1.(x+7/x+6)+(x+9/+x+8)=(x+10/x+9)+(x+6/x+5)(x+9/+x+8)-(x+10/x+9)=(x+6/x+5)-(x+7/x+6)(((x+9)^2-(x+8)(
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
13.2x+9x=33.38x-3x=105(13.2+9)x=33.3(8-3)x=10522.2x=33.35x=10522.2x÷22.2=33.3÷22.25x÷5=105÷5x=1.5x=2
/>因为:x-5/x-6+x-8/x-9=x-7/x-8+x-6/x-7,所以:1+1/(x-6)+1+1/(x-9)=1+1/(x-8)+1+1/(x-7)即:1/(x-6)+1/(x-9)=1/(
(1)(X+7)/(X+6)+(X+9)/(X+8)=(X+10)/(X+9)+(X+6)/(X+5)这类方程重在运算的技巧性,观察分母7+9=10+6;6+8=5+9所以先移项:(X+7)/(X+6
即1/(x-5)+1/(x-9)=1/(x-6)+1/(x-8)(2x-14)[1/(x-5)(x-9)-1/(x-6)(x-8)]=01/(x-5)(x-9)-1/(x-6)(x-8)≠0所以2x-
通分得[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),
(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(
13.2x+9x=33.322.2x=33.3x=1.58x-3x=1055x=105x=215.4x+3x=12.88.4x=12.8x=1.5238x-0.36x=160.64x=16x=25再问
首先回答:X7X-X7X=X98设被减数的百位数字是a,个位数字是b,其中(0
再答: 再问:还有,再答:
再答: 再答: 再答: 再问:错了再答:哪题?再答:哪题错了?
第二个是再答:5x=105
(X-4)/(X-5)-(X-5)/(X-6)=(X-7)/(X-8)-(X-8)/(X-9)[(x-4)(x-6)-(x-5)2]/(x-5)(x-6)=[(x-7)(x-9)-(x-8)2]/(x