已知:x-3y=0,求代数式3x 5y除以4
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绝对值只可能是正数或0正数之和不可能为0所以:X-2=0Y-1/3=0解得:X=2Y=1/33x+3y=3(x+y)=3(2+1/3)=7
7-x+y-(y-x)=7-(x-y)+(x-y)……(这步添括号,y-x=-(x-y),代入x-y=3)=7-3+3=77^2=49(7的平方等于49)
绝对值大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等于0所以x+y+1=0xy+3=0xy=-3x+y=-1两边平方x^2+2xy+y^2=(-1)^2x^2+y^2=1-
:|x+二分之一|+(y-3)的平方=0∴x+1/2=0y-3=0∴x=-1/2y=3(3x+2y)的平方-2(x-y)(x+y)+3(x+y)(x-2y)=9x²+12xy+4y²
绝对值大于等于0相加等于0则只有都等于0才成立所以X-2=0,Y+1/3=0X=2,Y=-1/32X+3Y=4-1=3
∵x+y=3,∴原式=3×32-43+2×3-3=2823.
|3-y|+|x+y|=0所以有3-y=0且x+y=0得:y=3,x=-3(x+y)/(xy)=0
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
x-y=1,x+y=-73(x+y)+20(x-y)-5=3×(-7)+20×1-5=-21+20-5=-6
|3-y|+|x+y|=0所以有3-y=0且x+y=0得:y=3,x=-3(x+y)/(xy)=0
原式=[(x+y)(x-y)/(x+y)]-2(x+y)=x-y-(2x+2y)=x-y-2x-2y=-x-3y=-(x+3y)=-2
7-x+y-(y-x)^2=7-(x-y)-(x-y)^2把x-y=3代入原式=7-3-3^2=-5
y(x-y)=3而3只有两个因数1和3,所以Y和(X-Y)肯定一个是1,一个是3所以Y是3,X-Y=1或者Y=1,x-y=3得到结果X=4,Y=3或者X=4,Y=1所以2x-3y=-1或者2x-3y=
7-x+y-(y-x)^2=7-(x-y)-(x-y)^2=7-3-3^2=4-9=-5
x/y=3/2则2x=3y带进去就变成6y-9y/(3y+3y)=-1/2y感觉怪怪的.一般都是转换下形式然后带进去这题怎么没一般项--或者直接将x=3y=2带进去
X*2+Y*2=(X+Y)*2__-2XY;因为X+Y=3;XY=2;所以X*2+Y*2=9-4=5.
∵x^2-3y^2=2xy∴x^2-2xy-3y^2=0∴(x+y)(x-3y)=0∵x>0,y>0∴x-3y=0∴x=3y∴x+2y/x-y=3y+2y/3y-y=2y+2/3或=2/3(x+1)如
x=0.5,y=23x平方y=1.5∵|2x-1|+|y-2|=0∴|2x-1|≥0,|y-2|≥0∴2x-1=0,y-2=0∴x=0.5,y=2∴3x平方y=1.5
解题思路:运用完全平方公式和平方差公式进行化简,再代入数值进行计算解题过程:解: