1. 用递归方法编写求斐波那契数列的函数,返回值为长整型.斐波那契数列的定义为
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/25 09:32:39
添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun
他的代码return1,是指序列从1开始,1,1,2,3,从0开始的话,改成if(k==0)return0;elseif(k==1)return1;elsereturnfib(k-1)+fib(k-2
为用了很没有效率的递归,所以出结果有点慢#includeiostream.h
帮你写好了.unsigned int fib(unsigned int n) {\x09if (n == 1
#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))
因为用了很没有效率的递归,所以出结果有点慢#includef(int);main(){inti,s=0;for(i=1;i
PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli
#includelongintf(intn){if(n==0)return0;elseif(n==1)return1;elsereturnf(n-1)+f(n-2);}intmain
// C++int F(int n) {if (n == 0) return 1;else if
#includeusingnamespacestd;intmain(){intn,a=1,b=2;cout再问:^那这个是什么符号,这个没学过,有用temp做的么?再答:是位运算的异或符号;也可以用t
functionfibonacci(n:integer):integerbeginif(n=0)thenResult:=0;if(n=1)thenResult:=1;if(n>1)thenResult
#includelongfib(intn){inta;if(n==1)a=1;elseif(n==2)a=1;elsea=fib(n-1)+fib(n-2);returna;}voidmain(){\
#include#includefloatmyfunction(intn,intx){if(0==n){return1;}elseif(1==n){returnx;}else{return((2*n-
publicclassFibonacci{\x09publicstaticvoidmain(Stringargs[]){intn,fn;//n为第n项,fn为第n项的值java.util.Scanne
方法1:#include"stdio.h"intfbnq(intd1,intd2,intn){intk;if(n>3){printf("%d,",d2);returnfbnq(d2,d1+d2,n-1
1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n
#includeintfibo(intn){if(nreturn1;elsereturnfibo(n-1)+fibo(n-2);}intmain(){intn;scanf("%d",&n);print
cleardimea[20]a[1]=1a[2]=1fori=3to20a[i]=a[i-1]+a[i-2]endforfori=1to30?a[i]if(i%5=0)?endifendfo
#includefib(intn){if(n==0)return(0);elseif(n==1)return(1);elsereturn(fib(n-1)+fib(n-2));}main(){intn
//fibonacci数列:11235813213455...#includedoublefib_val[100]={0};doublefibonacci_1(intn)//递归,计算时间长,n最好不