已知I2M-6I [3M-N-5]*[3M-N-5]=0
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已知-m+2n=5,那么(m-2n)²+6n-3m-60=__-20_____.-m+2n=52n-m=5m-2n=-56n-3m=3(2n-m)(m-2n)²+6n-3m-60=
∵2n-m=5∴m+5=2n5(m+5)²+6n-3m-60=5×4n²+6n-3(m+5)-45=20n²+6n-6n-45=20n²-45明教为您解答,如若
-m+2n=52n-m=55(m-2n)的平方+6n-3m-60=5*(2n-m)+3(2n-m)-60=5*25+3*5-60=80希望对你有所帮助如有问题,.
化简:[6m²-5m(-m+3n)+4m(-4m+5/2n)]=6m²+5m²-15mn-16m²+10mn=-5m²-5mn=-5m(m+n);而m
5(m-2n)²+6n-3m-3=5[-(-m+2n)]²+3(-m+2n)-3=5*(-2)²+3*2-3=20+6-3=23
5(m-2n)^2+6n-3m-3=5(-m+2n)^2+3(-m+2n)-3根据-m+2n=2,原式=5×2^2+3×2-3=23.第一步依据:a^2=(-a)^2
原式=5*2*2+3*2-3=20+6-3=23
由题可知,m方-3m-1=3且m方-5m-6=0解出来m=-1再问:复数Z=1+i,实数a,b满足az+2bz=(a+2z)方,求a,b的值再问:这题能帮我么?再答:等等哈再答:az+2bz=(a+2
m/(m+n)+m/(m-n)-n²/((m²-n²)=(m²-mn+m²+mn-n²)/(m²-n²)=(2m&sup
3x(M-5x)=6x^2y^3+N,3x*M-15x^2=6x^2y^3+NM=2xy^3N=-15x^2
M=2yN=-15x^2再问:可以发过程吗再答:前面有点写错了,少看了个平方再问:就是咯,再答:
由-m+2n=-6得m-2n=6将m-2n=6,代入3(m-2n)²-5(m-2n)-1得3×6²-5×6-1=108-30-1=77
应该是-m+2n=5吧=5(-m+2n)^2+3(-m+2n)-60=5*5^2+3*5-60=125+15-60=80
5(m-2n)^2+6n-3m-60=5(m-2n)^2+3(2n-m)-60=5*(-5)^2+3*5-60=80
题目应是:已知-m+2n=2,求5(m-2n)²+6n-3m-3的值已知-m+2n=2m-2n=-2,5(m-2n)²+6n-3m-3的值=5(-2)²+3(-m+2n)
答:-m+2n=5(m-2n)²+6n-3m-60=(-m+2n)²+3(2n-m)-60=5²+3*5-60=25+15-60=-20
已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)
5(m-2n)+6n-3m-60=-5(2n-m)+3(2n-m)-60=-2(2n-m)-60=-2×5-60=-10-60=-70
根据题意,若M∩N={1,3},则3∈M,而M={1,(m2-3m-1)+(m2-5m-6)i},则有(m2-3m-1)+(m2-5m-6)i=3,即(m2-3m-1)=3且(m2-5m-6)=0,解
5(m-2n)^2+6n-3m-60=5(-m+2n)^2+3(-m+2n)-60=5*5^2+3*5-60=125+15-60=80