已知x y=1,xy=-2分之1

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已知x y=1,xy=-2分之1
已知(x+1)²+|y-1|=0,求2(xy-5xy²)-(3xy²-xy)得值

解(x+1)平方+/y-1/=0∴x+1=0,y-1=0∴x=-1,y=1∴2(xy-5xy平方)-(3xy平方-xy)=(2xy+xy)+(-10xy平方-3xy平方)=3xy-13xy平方=3×(

搜索[4(xy-1)二次方-(xy+2)(2-xy)]除以4分之1xy,其中X=-2,Y=5分之1.怎么算

可以先设xy=t原式=[4(t-1)^2-(t+2)(2-t)]/(1/4*t)=4(4t^2-8t+4-2t+t^2-4+2t)/t=4(5t^2-8t)/t=(20t-32)/t=20-32/t将

当x=3,y=3分之1时,求代数出3xy-[2xy-2(xy-2分之3xy)+xy]+3xy的值

3xy-[2xy-2(xy-2分之3xy)+xy]+3xy=6xy-[2xy-2xy+3xy+xy)=6xy-4xy=2xy=2×3×3分之1=2

已知x分之1+y分之1=-2,则x+xy+y分之x-xy+y的值等于

1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3

已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=

xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7

已知:xy的平方=2,求代数式xy的平方·(-x的平方y的平方)·(2分之1xy的三次方)的平方

xy的平方·(-x的平方y的平方)·(2分之1xy的三次方)的平方=(xy)^2*(-x^2y^2)*(xy)^6/4=-(xy)^10/4=-[(xy)^2]^5/4=-2^5/4=-8

已知X+Y分之XY=2,求-X+3XY-Y分之3X+5XY+3Y

因为X+Y分之XY=2,所以XY=2(X+Y)代入后面的分子式得:13(X+Y)/5(X+Y)=13/5

1.已知x+y=-4,xy=3,求5(2分之1xy+2y)+[6x-(2xy+y-3x)]的值

1.已知x+y=-4,xy=3,求5(xy/2+2y)+[6x-(2xy+y-3x)]的值5(xy/2+2y)+[6x-(2xy+y-3x)]=5xy/2+10y+6x-2xy-y+3x=xy/2+9

已知(x分之1)+(y分之1)=5,求(x+2xy+y)分之(2x-3xy+2y)=?

(x分之1)+(y分之1)=5(x+y)/xy=5x+y=5xy代入(x+2xy+y)分之(2x-3xy+2y)=7xy分之7xy=1

已知:xy+x=-1,xy-y=-2.

(1)∵xy+x=-1①,xy-y=-2②,∴①-②得x+y=1;(2)先把xy+x=-1,xy-y=-2的值代入代数式,得原式=-x-[2y-1+3x]+2[x+4]=-x-2y+1-3x+2x+8

已知xx+xy=1,xy-yy=-4,则xx+2xy-yy=

xx+2xy-yy=-3两式相加即可

(x+2y-3xy+2x+y-xy)-(-2-y+xy),其中x+y=2分之1,xy=-2分之1

(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2

化简:xy分之3x^2+2xy-xy分之2x^2-xy=

(3x^2+2xy)/xy-(2x^2-xy)/xy=(3x^2+2xy-2x^2+xy)/xy=(x^2+3xy)/xy=x(x+3y)/xy=(x+3y)/y

已知x-y分之xy= - 3分之1,求x-2xy-y分之2x+3xy-2y的值

x-y分之xy=-3分之1xy分之(x-y)=-3x-y=-3xyx-2xy-y分之2x+3xy-2y=(-6xy+3xy)/(-3xy-2xy)=3/5

化简求值:[x(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy,其中x=-2,y=5分之1.

[4(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy=[4x^2乘以y^2-8xy+4-(4-x^2y^2)]除以4分之1xy=(4x^2乘以y^2-8xy+4-4+x^2y^2)除以4分

已知x分之1-y分之1=2,求2x-3xy-2y分之x-2xy-y的值.

∵1/x-1/y=2∴(y-x)/(xy)=2∴y-x=2xy∴2x-3xy-2y=2(x-y)-3xy=-4xy-3xy=-7xyx-2xy-y=x-y-2xy=-2xy-2xy=-4xy∴(x-2

已知x分之1-y分之1=-3,则则代数式3x-2xy-3y分之x=3xy-y=

x分之1-y分之1=-3所以(y-x)/xy=-3y-x=-3xy从而3x-2xy-3y分之x+3xy-y=(3xy+3xy)/(3×3xy-2xy)=6/7

已知2X-3√xy-2y=0(x>0)求2x²+xy-9y²分之x²+4xy-16y

①xy同非负时,2x-3√xy-2y=(2√x+√y)(√x-2√y)=0∴√x=2√y,x=4y②xy同负时,2x-3√xy-2y=[2√(-x)+√(-y)][√(-x)-2√(-y)]=0∴√(

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy),其中x=20,y=-25分之1

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+