已知x加y减2等于0_求-搜答案-大师作文网

应该是x^2-2x+y^2+6y+10=0配方：x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0得x=1y=-3所以x+y=-2

x^2-2x+y^2+6y+10=0(x-1)^2+(y+3)^2=0(x-1)^2=0x-1=0x=1(y+3)^2=0y+3=0y=-3x+y=1-3=-2

1/2再答：再问：谢谢了，问题解决了

x的平方-4x+y的平方+2y+5=x的平方-4x+4+y的平方+2y+1=(x-2)^2+(y+1)^2=0x-2=0x=2y+1=0y=-1x+y=2-1=1

再答：谢谢

x²+y²-2x+1=0(x-1)²+y²=0所以x-1=0y=0即x=1

已知x方加y方减2x加4y等于-5x方+y方-2x+4y+5=0x方-2x+1+y方+4y+4=0(x-1)方+(y+2)方=0所以x-1=0,y+2=0所以x=1,y=-2如果不懂,请追问,祝学习愉

x^2+2x+y^2-6y+10=0=(x^2+2x+1)+(y^2-6y+9)=0=(x+1)^2+(y^2-6y+3^2)=0=(x+1)^2+(y-3)^2=0x=-1y=3xy=-3

已知x加2的平方加3减y绝对值等于0,求xy减x减y的值（x+2）^2+/3-y/=0,（x+2）^2>=0,/3-y/>=0所以(x+2)=0x=-23-y=0y=3xy-x-y=-6+2-3=-7

x^2-2x+y^2+6y+10=0x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0x-1=0,y+3=0x=1,y=-3(x-y)/(x+y)=4/(-2)=-2

x^2+y^2+2x-4y+5=0,(x+1)^2+(y-2)^2=0,x=-1,y=2(-1)^2006-1/2=1-1/2=1/2

x^2+y^2+2x-6y+10=0(x^2+2x+1)+(y^2-6y+9)=0(x+1)^2+(y-3)^2=0平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立所以两个都等于0所

原等式可化为：x²-2xy+y²+6(x-y)+9+y²=0即：(x-y)²+6(x-y)+9+y²=0（x-y+3)²+y²=0

x=1,y=-3再问：过程再答：化简一下就得到方程（x-1）2+（y+3）2=0.这里的2表示平方啊，不知道怎么打平方。很明显只有x=1，y=-3才满足啊。

x²+y²+4x-6y+13=0(x+2)²+(y-3)²=0x+2=0、y-3=0x=-2、y=3

x^2+3y^2-12y+12=0x^2+3(y-2)^2=0所以x^2=0,3(y-2)^2=0x=0,y-2=0y=2y^x=2^0=1

x的平方加y的平方加4x减2y加5等于0(x+2)^2+(y-1)^2=0x+2=0y-1=0x=-2y=1

x²+y²-4x-2y+5=0x²-4x+4+y²-2y+1=0(x-2)²+(y-1)²=0x-2=0x=2y-1=0y=1√(x+y)/

X^2+4Y^2+2X-4Y+2=0(X^2+2X+1)+(4Y^2-4Y+1)=0(X+1)^2+(2Y-1)^2=0X=-1Y=1/2

x为-2,y为1