已知x加y等于5 xy等于6,求(1)x的平方y加xy的平方
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X+Y=5,XY=2,5X+4Y-3X-2Y+XY=2X+2Y+XY=2(X+Y)+XY=2×5+2=12.
(2X-3Y-2XY)-(X-4Y+XY)=2X-3Y-2XY-X+4Y-XY=X+Y-3XY因为x加y等于110,xy等于33所以原式等于:110-33*3=11
X²+Y²=10..(1)X+Y=6..(2)(2)²-(1)得2XY=26XY=13如果认为讲解不够清楚,
x^2+2x+y^2-6y+10=0=(x^2+2x+1)+(y^2-6y+9)=0=(x+1)^2+(y^2-6y+3^2)=0=(x+1)^2+(y-3)^2=0x=-1y=3xy=-3
xy分之x加y等于2∴x+y=2xy3x减5xy加3y分之负x加3xy减y=[-(x+y)+3xy]/[3(x+y)-5xy]=(-2xy+3xy)/(6xy-5xy)=xy/(xy)=1
(x-y)²=(x+y)²-4xy=25-12=13
求X2+5XY+30Y(X+5Y)2=62X2+25Y2+10XY=36(X2+5XY+30Y)+5XY+25Y2-30Y=36(X2+5XY+30Y)+5Y(X+5Y)-30Y=36(X2+5XY+
x-y=6;xy=-2;原式=3(xy+x-2y)-5(y-2x)+2(xy-x)=3xy+3x-6y-5y+10x+2xy-2x;=5xy+11x-11y=-10+66=56;请采纳如果你认可我的回
x+y=7y=7-xxy=x(7-x)=12x=3或4x=3,y=4或x=4,y=3x-y=1或-1
x方+y方+5/4=2x+y(x方-2x+1)+(y方-y+1/4)=0(x-1)方+(y-1/2)方=0x=1,y=1/2xy/(x+y)=1/3
由已知得x+y=10,xy=25-24=1,所以3x^2-5xy+3y^2=3(x+y)^2-11xy=300-11=289.
x=5-2√6,y=5+2√6x+y=(5-2√6)+(5+2√6)=10xy=(5-2√6)(5+2√6)=5²-(2√6)²=13x²-5xy+3y²=3(
解题思路:运用完全平方公式、整体代入可解解题过程:解:∵x+y=5,xy=3,∴2x²+2y²=2(x²+y²)=2[(x+y)²-2xy]=2×(5²-2×3)=38;(x-y)²=(x+y)²-4
x^2减6xy加9y等于0.则x:y等于_3:1___.
首先分母有理化,上下同乘以根号x加根号y,然后变成了(x+2乘以根号下xy+y)/(x-y)对xy=4开平方,得到根号下xy=2,(x-y)^2=(x+y)^2-4xy=9,你再开一下方就可以了得到(
(x+y)^2=x∧2+y∧2+2xy=9x∧2+y∧2=9-2×(-9)=27
x/y+y/x=(x²+y²)/xyx²+y²=(x+y)²-2xy=36-16=20原式=20/8=2.5
已知xy/(x+y)=2,求:(3x-5xy+3y)/(-x+3xy-y)xy/(x+y)=2得:xy=2(x+y)(3x-5xy+3y)/(-x+3xy-y)=(3x-9xy+3y+4xy)/(-x
根据(x+y)2=x2+y2+2xy,可得x2+y2=13
x^2y+xy^2=xy(x+y)=6×5=30