已知y=x^2-ax a 2在[0,1]上的最大值
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/07 07:33:21
(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y
P=x²/x-y-y²/x-y=(x²-y²)/(x-y)=(x+y)(x-y)/(x-y)=x+y当x=2,y=1时p=3Q=(x+y)²-2y(x
1.f(1)=f(1/1)=f(1)-f(1)=0f(2)=f(4/2)=f(4)-f(2),f(4)=2f(2)=2f(4)=f(8/2)=f(8)-f(2),f(8)=f(4)+f(2)=3题目错
x²+4x+y²+6y+13=x²+4x+4+y²+6y+9=(x+2)²+(y+3)²=0所以x+2=0;y+3=0所以x=-2,y=-3
设y=g(x)=a(x-b)(x-1)1=ab3=a(2-b)解得:a=2b=1/2g(x)=2(x-(1/2))(x-1)=2[x^2-(3/2)x+(1/2)]=2x^2-3x+1g'(x)=4x
√(2-x)+√(x-2)-y+3=0∵2-x≥0,x-2≥0∴x≤2,x≥2∴x=2∴-y+3=0y=3把x=2,y=3代入题目给的式子(你忘打了)中即可计算出结果.
X/X···这是什么意思···再问:x减y分之x等于x分之x减2y再答:两边同乘x(x-2y)再问:再答:题目是什么····就给个图啊···再问:如图,已知EFGH为矩形,AD⊥Bc于D,交HG于K,
x+y=m2x-y=6x=(m+6)/3y=(2m-6)/3x+y=m>0x-y=(12-m)/3>00
2x=2-3yx>0则2x>0所以2-3y>0y
x²-2x+y²+6y+10=0x²-2x+1+y²+6y+9=0(x-1)²+(y+3)²=0x-1=0y+3=0∴x=1y=-3∴x+y
x^2+2x+y^2-6y+10=0(x+1)²+(y-3)²=0∴x=-1,y=3(x+y)²=(-1+3)²=4
X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5
即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²
如果是(x-y)/x=x/x-2y,则x:y=2:3(x-y)/x=(x-2y+2y)/x-2y1-y/x=1+2y/(x-2y)-y/x=2y/(x-2y)x/y=(x-2y)/-2yx/y=-1/
最小值0.5,1.5,-1最大值1,1,-1/3约束区域是一个三角形,把三角形的三个顶点代入.可以检验出最大值最小值.
求得两圆交点为(0,2),(2,0),两圆交点的垂直平分线为:(x^2+y^2-2x-2y)-(x^2+y^2-4)=0,即x+y=2,与x-y=0的交点C为:(1,1),半径r=√[(1-0)^2+
∵y+x^2=0∴x+y=x-x^2=-(x-2)^2+1/4≤1/4∴x+y的最大值=1/4∵0
解方程X=(6+M)/3Y=2M/3-2因为x>0y-6m
∵x+2≥0,|y-3|≥0且x+2+|y-3|=0,∴x+2=0,|y-3|=0,∴x+2=0,y-3=0,解得x=-2,y=3,当x=-2,y=3时,x2+y2+3=(-2)2+32+3=16=4