已知y分之x等于3_求-搜答案-大师作文网

1/x-1/y=2y-x=2xyx-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=[-6xy+7xy]/[-4xy-3xy]=xy/[

设x/2=y/3=z/4=t则x=2t,y=3t,z=4t∴（x-y+2z)/(3x-y)【分子应该是x-y+2z】=(2t-3t+8t)/(6t-3t)=(7t)/(3t)=7/3再问：谢谢我这题写

答：1/x+1/y=3(x-2xy+y)/(2x+xy+2y)分子分母同除以xy得：=(1/y-2+1/x)/(2/y+1+2/x)=(3-2)/(3*2+1)=1/7

x/2=y/3=z/4=tx=2ty=3tz=4tx+y-z=1/122t+3t-4t=t=1/12x=1/6y=1/4z=1/3xyz=1/6*1/4/*1/3=1/72

(x²-2x)/(xy-2y)=x(x-2)/y(x-2)=x/y=3再问：不是应该提取相同的字母吗？再答：是提取相同的字母呀，(x²-2x)中相同的字母是x，那么就是x(x-2)

X=六分之一Y=四分之一Z=三分之一

解析：

设3分之x等于4分之y等于7分之z等于=kx=3ky=4kz=7k代数式y分之3x+y+z=(3*3k+4k+7k)/4k=20k/4k=5

因为1/x-1/y=3所以方程左边先通分得y/xy-x/xy=3即（y-x）/xy=3所以得y-x=3xy（这一步很关键,一会要用整体代入法)要求的分数的分子：x+xy-y=xy-3xy=-2xy(因

假设x分之3=y分之4=z分之5=1,则x=3,y=4,z=53x-2y+z分之x+y+z=(3x3-2x4+5)分之（3+4+5）=6分之12=2http://zhidao.baidu.com/li

x/3=y/4=z/5x=3/4y,z=5/4y(x+y-z)/(x-y+z)=(3/4y+y-5/4y)/(3/4y-y+5/4y)=1/2y/y=1/2

1/x-1/y=5通分(y-x)/xy=5y-x=5xyx-y=-5xy原式=[3(x-y)+5xy]/[(x-y)-3xy]=(-15xy+5xy)/(-5xy-3xy)=-10xy/(-8xy)=

1/x-1/y=3y-x=3xyx-y=-3xy(5x-xy-5y)/(x-xy-y)=(-15xy-xy)/(-3xy-xy)=4

x分之1减y分之1等于31/x-1/y=3(y-x)/xy=3y-x=3xy所以x-xy-y分之5x-xy-5y=（-3xy-xy）分之(-15xy-xy)=-4分之（-16）=4

3/4x=y/5,则x:y=4:15,y/5=z/6,则y:z=5:6,所以:x:y:z=4:15:18

设x+y=axy=b,则b/a=3b=3a所以-X+3XY-Y分之2X-3XY+2Y可以写成(2a-3b)/(3b-a)=-7/8

两边乘以8y8(x+y)=11y8x+8y=11y3y=8xy=(8/3)x原式分子=x+y=x+(8/3)x=(11/3)x分母=x+2y=x+2(8/3)x=(19/3)x所以原式=(11/3)x

x/3=y/4=z/5分开即可得到x/3=y/4和y/4=z/5x/3=y/4两边同时乘以倍数12,即可得到4x=3y所以x=3/4y同理y/4=z/5两边同时乘以相同倍数20,即可得到5y=4z所以

x/3=y/4=z/5x：Y：Z=3；4;5